What is the value of 2x3 + x2 – x when x = 3?

Mathematics

1 answer:

Bad White [126]3 years ago

7 0

Answer:

Step-by-step explanation:

This is assuming that x2 means x to the power of 2 and that the x on the left is to represent multiplying. First, plug in all of the number to get 2*3+3^2-3.Using PEMDAS, you should solve the exponent to get 9. Then, multiply 2 by 3 to get 6. Add 6 to 9 to get 15. Subtract 2 to 15 to get 12.

TL;DR

2*3+3^2-3

6+9-3

15-3

You might be interested in

PLEASE HELP!!

erik [133]

$2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha$

$1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}$

$3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x$

8 0

3 years ago

Layla borrowed some money from her friend in order to help buy a new video game

astra-53 [7]

Answer:

hi hru can you be my friend

8 0

2 years ago

Erik pays 225 in advance on his account at the athletic club. Each time he uses the club , $9 is deducted from the account , wri

zhenek [66]

Answer:

225÷ 9?