Let the weightage of Ease of Use be x
Ease of Use = x
<span>Compatibility is 5 times more than ease of use:
</span>Compatibility = 5x
<span>Reputation is 3 times more important than compatibility:
</span>Reputation = 3(5x) 
Reputation = 15x
<span>Cost is 2 times more important than reputation:
</span>Cost = 2(15x)
Cost = 30x
So the weightage are:
Ease of Use : 1
Compatibility : 5
Reputation :15
Cost : 30
        
             
        
        
        
No. the product stays the same because it is still the same number, just in fraction form. 
        
             
        
        
        
Answer:
Yes, the price the school pays each year in entrance fees is proportional to the number of students entering the zoo
Step-by-step explanation:
Relationships between two variables is proportional if their ratios are equivalent. 
In 2010, the school paid $1,260 for 84 students to enter the zoo.
Ratio of the price the school pays each year in entrance fees to the number of students entering the zoo = 
In 2011, the school paid $1,050 for 70 students to enter the zoo.
Ratio of the price the school pays each year in entrance fees to the number of students entering the zoo = 
In 2012, the school paid $1,395 for 93 students to enter the zoo.
Ratio of the price the school pays each year in entrance fees to the number of students entering the zoo = 
As  ,
,
the price the school pays each year in entrance fees is proportional to the number of students entering the zoo.
 
        
             
        
        
        
Answer:
The correct answer is 10 days.
Step-by-step explanation:
To fill a trench, 5 men work for 6 hours a day for eight days.
Total work hours required is given by 5 × 6 × 8 = 240 hours. 
The same work is supposed to be done by 3 men working 8 hours a day.
Let these three men need to work for x days.
Therefore total work hour these group of three men gave = 3 × 8 × x = 24x hours
Therefore the work hour of both the group of 5 men and 3 men should be equal.
⇒ 24x = 240
⇒ x = 10
Therefore the group of 3 men have to work for 10 days to fill the trench.