Given that the book value of the automobile that was purchased is 30,000 and is to be depreciated for 3 years using MACRS method of depreciation the value of the automobile at the end of the year is 8,640 dollars. This is computed by summing up the depreciation for the firswt 3 years which is equal to 71.2 per cent less 100 then it will be multiply to 30,000.
Step-by-step explanation:
Price of Jeans = $78.35
30% coupon = 30% × $78.35 = $23.51
6% sales tax = 6% × $78.35 = $4.70
1% local option tax = 1% × $78.35 = $0.78
Total cost of jeans = $78.35 - $23.51 + $4.70 + $0.78 = $60.32
Answer:
Step-by-step explanation:
so f-1(x) means we are finding the inverse
f(x) = 3x - 7.....change f(x) to y
y = 3x - 7.....now switch ur x and y and solve for y
x = 3y - 7....add 7 to both sides
x + 7 = 3y...divide both sides by 3
(x/3) + 7/3 = y....rearrange
y = (x/3) + 7/3....can also be written as : y = 1/3x + 7
now just change ur y to f-1(x)
f-1(x) = x/3 + 7/3.....or f-1(x) = 1/3x + 7/3
Answer:
x = -11/5 and y = 24/5
Step-by-step explanation:
Use elimination.
First, we need to multiply so that at least one variable can cancel out.
We can multiply the top equation by 2.
So we get
4x + 6y = 20
Then, we can use elimination.
The x's cancel out.
So we get 5y = 24
Or y = 24/5
Then, we can plug in this y value back into the first equation to find x.
2x + 3(24/5) = 10
2x + 72/5 = 50/5
2x = -22/5
x = -11/5
So x = -11/5 and y = 24/5
Answer:
Problem 1) frequency: 160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)
Problem 2) Runner B has the smallest period
Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.
Step-by-step explanation:
The frequency of the football player is 160 heartbeats per minute.
The period is (using the equation you showed above):
second problem:
Runner A does 200 loops in 60 minutes so his frequency is:
loops per minute
then the period is: 0.3 minutes (does one loop in 0.3 minutes)
the other runner does 200 loops in 65 minutes, so his frequency is:
loops per minute
then the period is:
Therefore runner B has the smaller period
