There are 4 red balls, 6 white balls, and 3 green balls in a bag. If one ball is drawn from the bag at random, what is the proba bility that it is not white?
A. 6/13
B. 1/7
C. 5/6
D. 7/13
2 answers:
Answer:
A
Step-by-step explanation:
i think its A because we have all balls together <em><u>1</u></em> <em><u>3</u></em> . Problem is asking about <em><u>6</u></em> <em><u> </u></em> <em><u>w</u></em> <em><u>h</u></em> <em><u>i</u></em> <em><u>t</u></em> <em><u>e</u></em> balls, that's why is 6/13:)
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Answer:
I would say yes
Step-by-step explanation: Hope I helped!
Answer:
Step-by-step explanation:
(27)^2/3=∛27²=∛3³*3³=3*3=9
√36³=√36*36*36=√6²*6²*6²=6*6*6=216
(-243)^3/5=5√2-42³=-27
Answer:
78.94
Step-by-step explanation:
It's the circle of life yeah yeah and it moves us all.
Answer:
3x / 2 + 9 = 5
3x / 2 = -4
3x = -8
x = -8/3
(2 + v) / 3 = 9
2 + v = 27
v = 25
32 / (d - 2) = 10
32 = 10 * (d - 2)
3.2 = d - 2
d = 5.2
2p - 4 = 3p / 2
2 * (2p - 4) = 3p
4p - 8 = 3p
p - 8 = 0
p = 8
3b / 2 = 12
3b = 24
b = 8
Answer:
809.69
Step-by-step explanation:
747.98(.0825)=61.708
747.98+61.708=809.688