Answer:
400 lb of salt
Step-by-step explanation:
Let us assume the water flows into the rank for x minutes.
There is an initial of 1000 gallons of water in the tank and water flows in through one pipe at 4 gal/min and through another pipe at 6 gal/min. In x minute, the amount of water in the tank = 1000 + 4x + 6x = 1000 + 10x
Water flows out at 5 gal/min, therefore in x minute the amount of water in the tank = 1000 + 10x - 5x = 1000 + 5x
The tank begins to overflow when it is full (has reached 1500 gallons). Therefore:
1500 = 1000 + 5x
5x = 1500 - 1000
5x = 500
x = 100 minutes.
1/2 lb salt per gallon flows into the tank at 4 gal/min and 1/3 lb of salt is flowing in at 6 gal/min, in 100 min the amount of salt that entered the tank = 4 gal/min × 100 min × 1/2 lb/gal + 6 gal/min × 100 min × 1/3 lb/gal= 400 lb
Therefore the amount of salt is in the tank when it is about to overflow = 400 lb of salt
Answer:
the pic is nit clear but nice pfp tanjiro from demon slayer
also if u don't mind me asking have you watched the mugen train
Answer:
Step-by-step explanation:
y = 4 - 3x + x^2 is to be rewritten in standard form. To do this, rearrange the terms in order of powers of x, from highest to lowest.
y = 4 - 3x + x^2 becomes y = x^2 - 3x + 4
Rewrite it as y=6x-7/5
Flip the x and y
x=6y-7/5
Solve
5x=6y-7
5x+7=6y
5/6x+7/6=y
f^-1(x)=5/6x+7/6
