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sergey [27]
4 years ago
15

Quick help: 7th grade hw question

Mathematics
1 answer:
Klio2033 [76]4 years ago
5 0
One rose is $2.50

You have $220

How I solved the total cost of one rose was I did 30/12 to get 2.5.

Then to solve my amount of money I have, I did 30 x 7 then I did 2.5 x 4 and added those totals together
.
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668 ÷ 35 show quotient as mixed number
yulyashka [42]
Quotient=19
remainder= 3
or
mixed number = 3/35 
7 0
3 years ago
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Find the mode for the data set.
jonny [76]
8.3 ; 8.7 ; 4.5 ; 6.9 ; 4.2 ; 11.7 ; 4

Arrange in order from least to greatest.

4 ; 4.2 ; 4.5 ; 6.9 ; 8.3 ; 8.7 ; 11.7

The mode is the number that appears the most in the data set. Every number only appeared once. So. there is no mode in the data set.

NO MODE.
7 0
3 years ago
Let c be the curve of intersection of the parabolic cylinder x2 = 2y, and the surface 3z = xy. find the exact length of c from t
Mandarinka [93]
Parameterize the intersection by setting x(t)=t, so that

x^2=2y\iff y=\dfrac{x^2}2\implies y(t)=\dfrac{t^2}2
3z=xy\iff z=\dfrac{xy}3\implies z(t)=\dfrac{t^3}6

The length of the path C is then given by the line integral along C,

\displaystyle\int_C\mathrm dS

where \mathrm dS=\sqrt{\left(\dfrac{\mathrm dx}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dz}{\mathrm dt}\right)^2}\,\mathrm dt. We have

\dfrac{\mathrm dx}{\mathrm dt}=1
\dfrac{\mathrm dy}{\mathrm dt}=t
\dfrac{\mathrm dz}{\mathrm dt}=\dfrac{t^2}2

and so the line integral is

\displaystyle\int_{t=0}^{t=2}\sqrt{1^2+t^2+\dfrac{t^4}4}\,\mathrm dt

This result is fortuitous, since we can write

1+t^2+\dfrac{t^4}4=\dfrac14(t^4+4t^2+4)=\dfrac{(t^2+2)^2}4=\left(\dfrac{t^2+2}2\right)^2

and so the integral reduces to

\displaystyle\int_{t=0}^{t=2}\frac{t^2+2}2\,\mathrm dt=\dfrac{10}3
3 0
3 years ago
divide the number 60 into 2 parts so that if one part is divided by 6 and the other part is divided by 8 the sum of the answer w
konstantin123 [22]
If we divide  60 into say hmmm two integers, and those integers are say "a" and "b", then  a + b = 60, therefore, a = 60 - b.

\bf \stackrel{\textit{one part is divided by 6}}{\cfrac{a}{6}}~~+~~\stackrel{\textit{the other part is divided by 8}}{\cfrac{b}{8}}~~=~~9
\\\\\\
\cfrac{60-b}{6}~~+~~\cfrac{b}{8}=9\impliedby 
\begin{array}{llll}
\textit{let's multiply both sides by}\\
\textit{the LCD of 24}
\end{array}
\\\\\\
24\left( \cfrac{60-b}{6}~~+~~\cfrac{b}{8} \right)=24(9)\implies 240-4b+3b=216
\\\\\\
-b=-24\implies b=\cfrac{-24}{-1}\implies b=24

what's the first integer?  well, a = 60 - b.
5 0
3 years ago
Divide. Round your answer to the nearest thousandth.
Kruka [31]

Answer:

8.254

Step-by-step explanation:

I used a calculator and then rounded it

5 0
3 years ago
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