Answer:
a) Since the distribution is normal, the distance from the mean to the upper limit is going to be the same as the distance from the mean to the lower limit. The mean is going to be the mid point between the limits, which is going to be the average of the limits. The limits are going to have a z score associated, in this case the upper z is 1.96 and the lower z is -1.96 as shown in the picture.
(4.4 + 6.0)/2 = 5.2
The mean for men is going to be 5.2 million cells/uL
b) The standard deviation for men can be calculated using the z score and the limit values. The formula is shown in the picture.
σ = (6.0 - 5.2)/1.96 = 0.4
The standard deviation is 0.4 million cells/uL
Answer:
Step-by-step explanation:
Answer:
1040
Step-by-step explanation:
5200x0.2=1040
Assuming x = side of the square,
Rectangle's dimensions =
Hope this helps. - M
Answer:
Step-by-step explanation:
We need to find the conditional probability P( T1 < s|N(t)=1 ) for all s ≥ 0
P( time of the first person's arrival < s till time t exactly 1 person has arrived )
= P( time of the first person's arrival < s, till time t exactly 1 person has arrived ) / P(exactly 1 person has arrived till time t )
{ As till time t, we know that exactly 1 person has arrived, thus relevant values of s : 0 < s < t }
P( time of the first person arrival < s, till time t exactly 1 person has arrived ) / P(exactly 1 person has arrived till time t )
= P( exactly 1 person has arrived till time s )/ P(exactly 1 person has arrived till time t )
P(exactly x person has arrived till time t ) ~ Poisson(kt) where k = lambda
Therefore,
P(exactly 1 person has arrived till time s )/ P(exactly 1 person has arrived till time t )
= [ kse-ks/1! ] / [ kte-kt/1! ]
= (s/t)e-k(s-t)
