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2 years ago

PLZ I NEED HELP I FORGOT HOW TO DO THIS

Mathematics

1 answer:

Fynjy0 [20]2 years ago

5 0

If it’s asking for the area, wouldn’t it be multiplying it so the answer would be 10560?

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Original price: $119.00; Markdown: 70%

Leokris [45]

The answer would be $35.70. 70% off would be $83.30 off of $119.

7 0

3 years ago

Read 2 more answers

Lukas graphed the system of equations shown.

vampirchik [111]

The system of equations 2x + 3y = 2 and y = (1/2)x + 3 have solutions at x = -2 and y = 2

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

From the system of equations 2x + 3y = 2 and y = (1/2)x + 3, the graph of the equation shows that the solution is at x = -2 and y = 2

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0

2 years ago

Please help! Write the intervals of the values shown on the graph below

Veseljchak [2.6K]

The answer is
-1 ≤ x < 3
We just learned this is in my algebra 2 AP class

5 0

2 years ago

You coach a basketball ball team of 12 players; 5 players must be on the floor at all times; Figuring that every player can play

makvit [3.9K]

The function "choose k from n", nCk, is defined as
nCk = n!/(k!*(n-k)!) . . . . . where "!" indicates the factorial

a) No position sensitivity.
The number of possibilities is the number of ways you can choose 5 players from a roster of 12.
12C5 = 12*11*10*9*8/(5*4*3*2*1) = 792
You can put 792 different teams on the floor.

b) 1 of 2 centers, 2 of 5 guards, 2 of 5 forwards.
The number of possibilities is the product of the number of ways, for each position, you can choose the required number of players from those capable of playing the position.
(2C1)*(5C2)*(5C2) = 2*10*10 = 200
You can put 200 different teams on the floor.

4 0

3 years ago

Consider a population list x, with a CV= 10%. A second population list, y, has a CV= 20%. The linear regression of y on x is y =

ch4aika [34]

Answer:

The correlation coefficient 0.5 depicts that there is moderate positive correlation between y and x.

Step-by-step explanation:

The linear regression equation is

y= a+bx

The given linear equation is

y= 10x

Here, slope=b=10 and intercept=a=0.

From above equation,

ybar=10xbar

We are given that CVx=0.1 and CVy=0.2

where CV=(standard deviation/mean)*100

We know that

b=r(Sy/Sx)

Multiplying by xbar/ybar on both sides

(xbar/ybar)b=r(Sy/Sx)(xbar/ybar)

(xbar/ybar)b=r[(Sy/ybar)/(Sx/xbar))]

(xbar/ybar)b=r[CVy/CVx]

As CVy/CVx=(Sy/ybar)*100/(Sx/xbar)*100=(Sy/ybar)/(Sx/xbar).

By putting ybar=10xbar, b=10, CVx=0.1 and CVy=0.2.

(xbar/10xbar)10=r(0.2/0.1)

1=r(0.2/0.1)

1=r(2)

r=0.5

There is moderate positive correlation between y and x.

6 0

3 years ago