Q = 6 and p = 5
It’s a parallelogram so the side opposite are the same.
6 = q - 3
Subtract 3 and add it to 6 and you get 9
9=q
Answer: it should be 10!
Step-by-step explanation:
the area of a triange is a=bh/2, so if you plug in your base and height, you get ten!
Answer:
x=9
Step-by-step explanation:
Add similar elements: -5x+3x=-2x
-2x+15=-3
Subtract 15 from both sides
-2x + 15-15=-3-15
Simplify
-2x=-18
Divide both sides by -2
-21/-2 = -18/-2
Simplify
x=9
Answer:
correct choice is option 3 - figure C.
Step-by-step explanation:
When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places. This gives you such reflection rule:
From the diagram:
L(3,1), M(4,3), N(5,3) and P(4,1).
Using the reflection rule, you can find coordinates of image points:
L'(1,3), M'(3,4), N'(3,5) and P'(1,4).
As you can see, these are coordinates of vertices of the figure C.
<em>on e2020 its c </em>
<em>give brainliest if this helps please (;</em>
<span>The two points that are most distant from (-1,0) are
exactly (1/3, 4sqrt(2)/3) and (1/3, -4sqrt(2)/3)
approximately (0.3333333, 1.885618) and (0.3333333, -1.885618)
Rewriting to express Y as a function of X, we get
4x^2 + y^2 = 4
y^2 = 4 - 4x^2
y = +/- sqrt(4 - 4x^2)
So that indicates that the range of values for X is -1 to 1.
Also the range of values for Y is from -2 to 2.
Additionally, the ellipse is centered upon the origin and is symmetrical to both the X and Y axis.
So let's just look at the positive Y values and upon finding the maximum distance, simply reflect that point across the X axis. So
y = sqrt(4-4x^2)
distance is
sqrt((x + 1)^2 + sqrt(4-4x^2)^2)
=sqrt(x^2 + 2x + 1 + 4 - 4x^2)
=sqrt(-3x^2 + 2x + 5)
And to simplify things, the maximum distance will also have the maximum squared distance, so square the equation, giving
-3x^2 + 2x + 5
Now the maximum will happen where the first derivative is equal to 0, so calculate the first derivative.
d = -3x^2 + 2x + 5
d' = -6x + 2
And set d' to 0 and solve for x, so
0 = -6x + 2
-2 = -6x
1/3 = x
So the furthest point will be where X = 1/3. Calculate those points using (1) above.
y = +/- sqrt(4 - 4x^2)
y = +/- sqrt(4 - 4(1/3)^2)
y = +/- sqrt(4 - 4(1/9))
y = +/- sqrt(4 - 4/9)
y = +/- sqrt(3 5/9)
y = +/- sqrt(32)/sqrt(9)
y = +/- 4sqrt(2)/3
y is approximately +/- 1.885618</span>