Answer:
Y = 3x^x is a graph that has exponential growth while y = 3^-x has exponential decay.
Y = 3x^x (-∞, 0) and (∞, ∞).
Y = 3x^-x (-∞, ∞) and (∞, 0).
Step-by-step explanation:
The infinity symbols were being used to represent the x and y values of each graph. I will call y = 3^x "graph 1" and y = 3^-x "graph 2".
When graph 1 had positive ∞ for its x value, its y value was reaching towards positive ∞. When its x was reaching for negative ∞, its y was going for 0.
For graph 2, however, when its x was reaching for positive ∞, its x was reaching for 0. When its x was reaching for negative ∞, its y was going for positive ∞.
Here's an image of the graphs:
Answer:
no hablo español lo siento sorry
With the way the equation is written, we can assume that the “x2” is x multiplied by 2.
The x2 and 9x are like terms, and can be simplified to 11x.
Our new equation is
f(x) = 11x + 18
With no exponential functions in the equation, the difference of each value’s output would be 11.
Answer:
x is 13.03
Step-by-step explanation:
Start by determining the length of the horizontal side of one of the triangles shown. The Pythagorean Theorem applies here:
(horizontal side)² + 17² = 19², so that:
(horizontal side)² + 17² = 19² - 17², or 72
Then the length of the horizontal side is +√72, or √36√2, or 6√2.
From the diagram it is obvious that the width of the rectangle, x, can be found by subtracting twice the length of the horizontal side of one of the triangles from 31 (base of the entire figure):
x = 31 - 2(6√2) = 13.03
x is 13.03