Answer:
(2/3, 13/3) (Exactly one solution)
Step-by-step explanation:
Write these equations in a column:
x+y=5
2x-y=-3
Note that we can eliminate y immediately by adding these two equations together. We get:
3x = 2, so that x = 2/3.
Substituting 2/3 for x in the first equation, we get:
2/3 + y = 5. Clear out fractions by multiplying all three terms by 3:
2 + 3y = 15, or 3y = 13. Then y = 13/3, and the solution is
(2/3, 13/3) There is exactly one solution.
Answer:
49 x^4 - 4 = 0
(7 x^2 - 2) (7 x^2 + 2) = 0
Only the first term will have real roots
7 x^2 = 2
x = (2 / 7)^1/2 = .535 or -.535
Answer:
B)
Step-by-step explanation:
Answer: 16) Vertex = (3, 39)
17) Vertex = (-2, -17)
<u>Step-by-step explanation:</u>
When given the standard form of a quadratic equation: ax² + bx + c
use the Axis of Symmetry formula to find the x-value of the vertex. x = -b/(2a)
Then plug the x-value into the given equation to find the y-value.
16) y = -x² + 6x + 30
↓ ↓ ↓
a= -1 b=6 c=30

Max: y = -(3)² + 6(3) + 30
= -9 + 18 + 30
= -9 + 48
= 39
Vertex: (3, 39)
***************************************************************************************
17) y = 3x² + 12x - 5
↓ ↓ ↓
a= 3 b=12 c= -5

Min: y = 3(-2)² + 12(-2) - 5
= 3(4) - 24 - 5
= 12 - 29
= -17
Vertex: (-2, -17)
Answer:
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Step-by-step explanation:
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