Answer:
The solution of |3x-9|≤15 is [-2;8] and the solution |2x-3|≥5 of is (-∞,2] ∪ [8,∞)
Step-by-step explanation:
When solving absolute value inequalities, there are two cases to consider.
Case 1: The expression within the absolute value symbols is positive.
Case 2: The expression within the absolute value symbols is negative.
The solution is the intersection of the solutions of these two cases.
In other words, for any real numbers a and b,
- if |a|> b then a>b or a<-b
- if |a|< b then a<b or a>-b
So, being |3x-9|≤15
Solving: 3x-9 ≤ 15
3x ≤15 + 9
3x ≤24
x ≤24÷3
x≤8
or 3x-9 ≥ -15
3x ≥-15 +9
3x ≥-6
x ≥ (-6)÷3
x ≥ -2
The solution is made up of all the intervals that make the inequality true. Expressing the solution as an interval: [-2;8]
So, being |2x-3|≥5
Solving: 2x-3 ≥ 5
2x ≥ 5 + 3
2x ≥8
x ≥8÷2
x≥8
or 2x-3 ≤ -5
2x ≤-5 +3
2x ≤-2
x ≤ (-2)÷2
x ≤ -2
Expressing the solution as an interval: (-∞,2] ∪ [8,∞)
Answer:
23 and 25
Step-by-step explanation:
x and x+2
x+3(x+2)=98
x+3x+6=98
4x=92
x=23
x+2=25
Answer:
10 and 12
Step-by-step explanation:
let the consecutive even integers be n and n + 2 , then
n² - 64 = 3(n + 2) ← distribute parenthesis
n² - 64 = 3n + 6 ( subtract 3n + 6 from both sides )
n² - 3n - 70 = 0 ← in standard form
(n - 10)(n + 7) = 0 ← in factored form
Equate each factor to zero and solve for n
n - 10 = 0 ⇒ n = 10
n + 7 = 0 ⇒ n = - 7
Since n must be a positive even integer then n = 10 and n + 2 = 10 + 2 = 12
The 2 numbers are 10 and 12
Answer:
1/96 or 0.01041666667
Step-by-step explanation:
