$\bf x^3-2x^2+5x-10=0\implies \stackrel{\textit{doing some grouping}}{(x^3-2x^2)+(5x-10)}=0 \\\\\\ \stackrel{\textit{common factoring}}{x^2\underline{(x-2)}+5\underline{(x-2)}}=0\implies \stackrel{\textit{more common factoring}}{\underline{(x-2)}(x^2+5)}=0 \\\\[-0.35em] ~\dotfill\\\\ x-2=0\implies x=2~~~~\textit{\large\checkmark} \\\\[-0.35em] ~\dotfill\\\\ x^2+5=0\implies x^2=-5\implies x=\sqrt{-5}\implies x=i\sqrt{5}\quad \bigotimes$

7 0

2 years ago

What is the solution to the inequality > 20?<br><br> x 4<br> x 100

professor190 [17]

Answer:

100

Step-by-step explanation:

7 0

2 years ago

I don’t know how to do this problem and need help getting answer?

3241004551 [841]

Hi!!! So to do this problem, you need to find the mean values for each sample. I will walk you through finding the mean of sample 1: first you want to add all of the values for sample 1, which are 4,5,2,4 and 3. Once you add those values you get 18. Then you must divide that 18 by the number of terms you added. The numbers you added were 4,5,2,4 and 3 like I said earlier which is 5 numbers. You divide 18 by 5 to get your mean, which is 3.6

Answer: (B) Sample 2

sample 1 mean = 3.6

sample 2 mean = 4.2

sample 3 mean = 3.8

sample 4 mean = 4

8 0

2 years ago

Help me plz and thank you

Kay [80]

The second one - 6/21

3 0

2 years ago