1) If a sound with the same amplitude and energy is propagated at a source, predict through which medium the sound will travel t
1 answer:
Answer:
denser media the speed is greater
Explanation:
The speed of sound is given by the relation
where B is the volume modulus and ρ the density of the medium
When analyzing the previous expression, the amplitude of the sound depends on the energy carried by the wave.
Wave speed, is given by the relationship between two magnitudes, we analyze their values for different media. The volume modulus for gases has values of the order of 10⁵ Pa, for liquids of the order of 10⁹ Pa and for solids of 10¹⁰ to 10¹¹ Pa, while the density has values of the order of 10⁻¹ to 10⁰ kg / m³ for gases for liquids 10³ kg / m³ and for solids of the order of 10³ to 10⁴ kg / m³
let's find the order of magnitude of the speed of sound
Gases
v =√ 10⁵/10⁰ = 300 m / s
liquids
v =√ 10⁹/10³ = 1000 m / s
solid
v = √ 10¹¹/ 10⁴ = 3000 m / s
We can see that in denser media the speed is greater
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Answer:
Magnitude of static friction force is 70 sin40° = 44.99 N.
No, it is not necessary that it is maximum static friction.
Normal force is equal to 70 cos40° = 53.62 N.
Explanation:
We apply newton law of moton equation along the plane and perpendicular to plane;
Along the plane,
70 sin 40° = ---------------(1)
70 cos 40° = N --------------(2)
= μN -----------------(3)
So, it depends on the value of μ that the friction is maximum or not .
Answer:
The answer is below
Explanation:
a) The change in energy is the difference between the final energy and the initial energy.
ΔE (energy change) = Ef (final energy) - Ei (initial energy)
The negative sign shows that energy is lost to the environment. Hence 0.334 J is lost to the environment.
b) According to the law of conservation of energy, energy cannot be created or destroyed but transformed from one form to another.
The oscillating object loses energy due to wind resistance, friction between the spring and the object. Given that the air is frictionless, hence the energy loss is due to friction which is converted to heat.
Complete question:
In the movie The Martian, astronauts travel to Mars in a spaceship called Hermes. This ship has a ring module that rotates around the ship to create “artificial gravity” within the module. Astronauts standing inside the ring module on the outer rim feel like they are standing on the surface of the Earth. (The trailer for this movie shows Hermes at t=2:19 and demonstrates the “artificial gravity” concept between t= 2:19 and t=2:24.)
Analyzing a still frame from the trailer and using the height of the actress to set the scale, you determine that the distance from the center of the ship to the outer rim of the ring module is 11.60 m
What does the rotational speed of the ring module have to be so that an astronaut standing on the outer rim of the ring module feels like they are standing on the surface of the Earth?
Answer:
The rotational speed of the ring module have to be 0.92 rad/s
Explanation:
Given;
the distance from the center of the ship to the outer rim of the ring module r, = 11.60 m
When the astronaut standing on the outer rim of the ring module feels like they are standing on the surface of the Earth, then their centripetal acceleration will be equal to acceleration due to gravity of Earth.
Centripetal acceleration, a = g = 9.8 m/s²
Centripetal acceleration, a = v²/r
But v = ωr
a = g = ω²r
Therefore, the rotational speed of the ring module have to be 0.92 rad/s