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Nadya [2.5K]
4 years ago
8

A point charge q1 = is located at the center of a thick conducting spherical shell of inner radius a = 2.2 cm and outer radius b

= 4.5 cm, The conducting spherical shell has a net charge of q2 = 2.6 μC. 1)What is Ex(P), the value of the x-component of the electric field at point P, located a distance 8.8 cm along the x-axis from q1?
Physics
1 answer:
Yanka [14]4 years ago
7 0

Answer:

Ex(P) = -3.602 x 10^6 N/C

Explanation:

  • given q1 = -5.7μC
  • q2 = 2.6 μC = the net charge on the conducting shell
  • inner radius of conducting shell = a = 2.2 cm =0.022m
  • outer radius of conducting shell = b = 4.5 cm = 0.045m

1) To get Ex(P), the value of the x-component of the electric field at point P, located a distance 8.8 cm along the x-axis from q1 ;

Ex(P) = k(q1+q2)/r^2

= 9 x 10^9 (-5.7 + 2.6) x 10^-6 /0.088^2

Ex(P) = -27.9 x 10^3/ 0.007744

Ex(P) = -3.602 x 10^6 N/C

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