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ICE Princess25 [194]
3 years ago
10

What is the basic formula for the harmonic of a standing wave

Physics
2 answers:
lisabon 2012 [21]3 years ago
6 0

The basic formula for the harmonic of a standing wave, describing the relation between the length and the wavelength is, L=\left(\frac{n}{2}\right) \lambda

<u>Explanation:</u>

Standing waves are produced if two waves of same frequencies interfere each other in such a way that it produce points that appears to be standing still in the medium.  

On studying the wave patterns analytically, we see that there is a direct relationship between the length of the medium in which the wave pattern is seen and the wavelength of the waves.

With other experimental researches and studies, it has been concluded that the length of the medium that draws a string covered by a harmonic of a standing wave is equal to half of wavelength of the wave pattern i.e., the equation for the nth harmonic of a standing wave is,

               L=\left(\frac{n}{2}\right) \lambda

Where,

L- Length of the string covered by the single loop of a complete wave

n- An integer representing the harmonic number

Pie3 years ago
4 0

fn=nf1 is the formula

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 A car whose initial speed is 30 m/s slows uniformly to 10 m/s in 5 seconds. Determine the acceleration of the car. Sketch a gra
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  • Initial velocity=u=30m/s
  • Final velocity=v=10m/s
  • Time=5s

\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{10-30}{5}

\\ \sf\longmapsto Acceleration=\dfrac{-20}{5}

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Now

For the second question

  • Time=3s

Using 2nd equation of motion

\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2

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5 0
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A 3 kg block is released from rest to slide down a ramp with friction. The length that the block slides is 2 meters and the angl
Arte-miy333 [17]

Answer:

(a). The acceleration is 3.20 m/s².

(b). The amount of work done by each force is 19.2 J.

(c). The total work done on the block is 19.2 J.

(d). The final speed of the block is 6.26 m/s.

Explanation:

Given that,

Mass of block = 3 kg

Distance = 2 m

Angle = 30°

Coefficient of kinetic friction = 0.20

(a). We need to calculate the acceleration

Using balance equation of force

N = mg\co\theta

mg\sin\theta-f_{k}=ma

a = g\sin\theta-\mu g\cos30

Put the value into the formula

a=g(\sin30-0.20\cos30)

a=9.8(\dfrac{1}{2}-0.20\times\dfrac{\sqrt{3}}{2})

a=3.20\ m/s^2

The acceleration is 3.20 m/s².

(b). We need to calculate the amount of work done by each force

Using formula of work done

Normal force is

N = mg\cos30

So due to this the net force is zero then the no work done by reaction force.

By another force,

W= F\times d

W=ma\times d

Put the value into the formula

W= 3\times3.20\times2

W=19.2\ J

The amount of work done by each force is 19.2 J.

(c). We need to calculate the total work done on the block

The total work done on the block is 19.2 J.

(d). We need to calculate the final speed of the block

Using equation of motion

v^2=u^2+2gs

Put the value into the formula

v^2=0+2\times9.8\times2

v=\sqrt{2\times9.8\times2}

v=6.26\ m/s

The final speed of the block is 6.26 m/s.

Hence, This is the required solution.

4 0
3 years ago
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