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3 years ago

What is the basic formula for the harmonic of a standing wave

2 answers:

lisabon 2012 [21]3 years ago

6 0

The basic formula for the harmonic of a standing wave, describing the relation between the length and the wavelength is, $L=\left(\frac{n}{2}\right) \lambda$

Explanation:

Standing waves are produced if two waves of same frequencies interfere each other in such a way that it produce points that appears to be standing still in the medium.

On studying the wave patterns analytically, we see that there is a direct relationship between the length of the medium in which the wave pattern is seen and the wavelength of the waves.

With other experimental researches and studies, it has been concluded that the length of the medium that draws a string covered by a harmonic of a standing wave is equal to half of wavelength of the wave pattern i.e., the equation for the nth harmonic of a standing wave is,

$L=\left(\frac{n}{2}\right) \lambda$

Where,

L- Length of the string covered by the single loop of a complete wave

n- An integer representing the harmonic number

Pie3 years ago

4 0

fn=nf1 is the formula

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The _______ is the time required for one complete wave oscillation to occur.

aleksandrvk [35]

Period is the answer

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3 years ago

Read 2 more answers

a catcher "gives" with the ball when he catches a 0.196 kg baseball moving at 31 m/s. if he moves his glove a distance of 5.32 c

Aloiza [94]

Answer:

3540.5N

Explanation:

Step one:

given data

mass m= 0.196kg

speed v= 31m/s

distance r= 5.32cm = 0.0532m

Step two

The expression relating force, mass, velocity and distance is

F= mv^2/r

substitute we have

F=0.196*31^2/0.0532

F=0.196*961/0.0532

F=188.356/0.0532

F=3540.5N

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3 years ago

Una locomotiva traina un solo vagone, che ha la sua stessa massa, con la forza di

gregori [183]

Answer:

c) F = 16000 N

Explanation:

For this exercise we use Newton's second law

F = ma

they tell us that adding the other wagons the acceleration of the locomotive must be maintained

F = m a

by adding the other four wagons

mass = 4 no

therefore to maintain the force you must also raise the same factor

Fe = 4Fo

Fe = 4 4000

F = 16000 N

3 0

3 years ago

A 800-gram grinding wheel 27.0 cm in diameter is in the shape of a uniform solid disk. (We can ignore the small hole at the cent

SSSSS [86.1K]

Explanation:

d = Diameter of wheel = 27 cm

r = Radius = $\frac{d}{2}=\frac{27}{2}=13.5\ cm$

m = Mass of wheel = 800 g

$\omega_i$ = Initial angular velocity = $245\times \frac{2\pi}{60}\ rad/s$

Equation of rotational motion

$\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{0-245\times \frac{2\pi}{60}}{50}\\\Rightarrow \alpha=-0.51312\ rad/s^2$

Moment of inertia is given by

$M=\frac{1}{2}mr^2\\\Rightarrow M=\frac{1}{2}\times 0.8\times 0.135^2\\\Rightarrow M=0.00729\ kgm^2$

Torque is given by

$\tau=I\alpha\\\Rightarrow \tau=0.00729\times -0.51312\\\Rightarrow \tau=-0.0037406448\ Nm$

The torque the friction exerts is -0.0037406448 Nm

For more information on torque and moment of inertia refer

brainly.com/question/13936874

brainly.com/question/3406242

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3 years ago

A bar magnet is dropped from above and falls through the loop of wire. The north pole of the bar magnet points downward towards

8_murik_8 [283]

Answer:

b. The current in the loop always flows in a counterclockwise direction.

Explanation:

When a magnet falls through a loop of wire, it induces an induced current on the loop of wire. This induced current is due to the motion of the magnet through the loop, which cause a change in the flux linkage of the magnet. According to Lenz law, the induced current acts in such a way as to repel the force or action that produces it. For this magnet, the only opposition possible is to stop its fall by inducing a like pole on the wire loop to repel its motion down. An induced current that flows counterclockwise in the wire loop has a polarity that is equivalent to a north pole on a magnet, and this will try to repel the motion of the magnet through the coil. Also, when the magnet goes pass the wire loop, this induced north pole will try to attract the south end of the magnet, all in a bid to stop its motion downwards.

3 0

3 years ago