Answer:
option 4 and 6
Step-by-step explanation:
Complementary angles --- they add up to 90 degrees
Answer:
Solution given:
The volume of two similar solids are 128 m³
and 250 m³.
surface area of larger solid is 250m²
<u>let</u><u> </u><u>surface</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>smaller</u><u> </u><u>solid</u><u> </u><u>be</u><u> </u><u>x</u><u>.</u>
<u>Since</u><u> </u><u>they</u><u> </u><u>are</u><u> </u><u>similar</u>

x=128
the surface are of the
smaller solid is 128m²
A = l x w
so you know that the length is 3m longer than the width, so you could use a formula to represent that
w = l + 3
you then substitute the second equation into the first to solve for l
70 = l x (l +3)
70 = l^2 + 3l
you could then rearrange the formula and solve for l using the quadratic formula
0 = l^2 + 3l - 70
l = -3 +- (square root (3)^2 - 4(1)(70)) / 2(1)
l = -3 +- (square root 9 + 280) / 2
l = -3 +- (square root 289) / 2
l = -3 +- 17 / 2
then you solve for the two seperate roots
l = -3 + 17 /2
l = 14 / 2
l = 7
or
l = -3 - 17 / 2
l = -20 / 2
l = -10
since a length cannot be negative, this root is not viable. therefore l = 7
to solve for w you would use
w = l + 3
w = 7 + 3
w = 10
hope this helps! if you did not understand a step or concept please let me know!