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MAVERICK [17]
3 years ago
14

A cylinder has a radius of 2 meters and a height of 10 meters. What is the volume of the cylinder? Cylinder V = Bh 1. Write the

formula replacing B with the formula for the area of a circle: 2. Substitute the actual measures for the variables: 3. Evaluate the power: V = πr2h V = π(22)(10) V = π(4)(10) 4. Simplify: V = π m3
Mathematics
1 answer:
Maru [420]3 years ago
6 0

Answer:

V = πr^2h

V = 40π m^3

Step-by-step explanation:

volume of a cylinder

V = Bh,

where B = area of the base

When the base is a circle, then the area of the base is

B = πr^2

Then the volume of the cylinder is

V = πr^2h

You are given the radius is 2 m, and the height is 10 m, so you have

r = 2 m, and h = 10 m

V = π(2 m)^2(10 m)

V = π(4)(10) m^3

V = 40π m^3

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Vlad1618 [11]

Answer:

Step-by-step explanation:

first the formula for frequency is f=1/t

some then the answer is f= 1/40

                                          f= 0.025

6 0
3 years ago
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Consider the function , f(x)=4x-5 what is the domain value that correspond to an output of f(x) = 11
kati45 [8]

Answer:

x = 4

Step-by-step explanation:

given f(x) = 11 then equate f(x) = 11 and solve for x

4x - 5 = 11 ( add 5 to both sides )

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3 years ago
Please help I need to answer this question and I am lost
marin [14]

Answer: vv hvvh hjhbhh

Step-by-step explanation:

8 0
3 years ago
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Rewrite <br><img src="https://tex.z-dn.net/?f=%20%7Bcos%7D%5E%7B4%7D%20x" id="TexFormula1" title=" {cos}^{4} x" alt=" {cos}^{4}
erastovalidia [21]

All you need is the double angle identity:

\cos^2x=\dfrac{1+\cos2x}2

So we have

\cos^4x=(\cos^2x)^2=\left(\dfrac{1+\cos2x}2\right)^2=\dfrac{1+2\cos2x+\cos^22x}4

Apply the identity again to the squared term:

\cos^4x=\dfrac{1+2\cos2x+\frac{1+\cos4x}2}4=\dfrac{3+4\cos2x+\cos4x}8

6 0
3 years ago
In relation t a functions? Is the inverse of relation t function
frozen [14]

Answer:

Relation t is a function. The inverse of relation t is not a function ⇒ 3rd

Step-by-step explanation:

* Lets explain how to solve the problem

- A relation is a set of inputs and outputs, and a function is a relation

 with one output for each input

- Ex: T = {(1 , 2) , (3 , 5) , (-4 , 0)} is a function because every input has

  only one output

- To find the inverse of a function we switched the input and the

  out put

- The inverse of a function may not always be a function

* Lets solve the problem

∵ The relation t is the set of ordered pairs of x and y

  x = 0     2      4    6

  y = -8    -7    -4    -4

∵ x = 0 has only y = -8

∵ x = 2 has only y = -7

∵ x = 4 has only y = -4

∵ x = 6 has only y = -4

∴ Every value of x has only one value of y

∴ Relation t is a function

* Lets find its inverse by switching x and y

∵ The inverse function of t is :

   x = -8     -7     -4    -4

   y =  0      2      4     6

∵ x = -8 has only y = 0

∵ x = -7 has only y = 2

∵ x = -4 has y = 4 and y = 6

∴ Not every value of x has only one value of y

∴ The inverse of relation t is not a function

* Relation t is a function. The inverse of relation t is not a function

4 0
3 years ago
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