3 years ago

Find the number of the natural numbers between 101 and 999 which are divisible by both 2 and 5 in AP

Mathematics

1 answer:

yaroslaw [1]3 years ago

8 0

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$110,120,130,...,990$

$n = \frac{990 - 110}{10} + 1 \\$

$n = \frac{880}{10} + 1 \\$

$n = 88 + 1$

$n = 89$

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