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kari74 [83]
2 years ago
8

If yuri has 20 books in each shelve and there are 6 bookshelves how many book are in the bookcase

Mathematics
1 answer:
Tasya [4]2 years ago
8 0

20 books per shelf  × 6 shelves = 120 books

Answer: 120

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Negitive 8 over 2 divided by 6 over negitive 3 = ??????
solmaris [256]

when you didve fractions flip the second one over and multiply

 so -8/2 divided by 6/-3 will become

-8/2 times -3/6

then multiple straight across so -8 x -3 = 24

over 6 time 2 = 12

 so you get 24/12 which equals 2

5 0
2 years ago
Read 2 more answers
(3n)^3 without exponents
aniked [119]
It will be 3n x 3n x 3n 

hope this helps
7 0
3 years ago
When solving a system of inequalities, which of the following methods are used? A.guess and check
yarga [219]

Answer:

Option B - graphing is the correct answer.

Step-by-step explanation:

To solve a system of inequalities we need graphing. Inequality tells us about the relative size of two values. When we graph the x and y co-ordinates, the solution is not the drawn line, but the area of the coordinate plane that satisfies the inequality. In inequalities, multiple solutions can be possible.

Plug and chug method does not a complete solution, it only tells where a point belongs. Guess and check does not apply here.

7 0
3 years ago
A textbook search committee is considering
lora16 [44]

Number of ways to select 3 books from 13 books for adoption is 286 .

<u>Step-by-step explanation:</u>

A Permutation is an ordered Combination. When the order does matter it is a Permutation. There are basically two types of permutation:

  • Repetition is Allowed: such as the lock above. It could be "333".
  • No Repetition: for example the first three people in a running race. You can't be first and second.

Formula is given by:

nC_r= \frac{n!}{r! (n-r)!} , where n is the number of things to choose from,  and we choose r of them,  no repetitions,  order matters. Here , n=13 , r=3.

⇒ 13C_3 = \frac{13!}{3!(13-3)!}

⇒ 13C_3 = \frac{13!}{3!(10)!}

⇒ 13C_3 = \frac{13(12)(11)10!}{3(2)(1)(10)!}

⇒ 13C_3 = 13(2)(11)

⇒ 13 C_3 = 286

∴ Number of ways to select 3 books from 13 books for adoption is 286 .

3 0
2 years ago
PLZ HELP!!!!
kherson [118]

Answer:

a=1 b=4 c=-5

Step-by-step explanation:

7 0
2 years ago
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