9514 1404 393
Answer:
a) The new triangle is a reflection of the original across the origin. All angles, segment lengths, and line slopes have been preserved: the transformed triangle is congruent with the original.
b) The new triangle is a reflection of the original across the origin and a dilation by a factor of 2. Angles have been preserved: the transformed triangle is similar to the original. The transformation is NOT rigid.
Step-by-step explanation:
1. The transformed triangle is blue in the attachment. It is congruent with the original. The transformation is "rigid," a reflection across the origin. All angles and lengths have been preserved, as well as line slopes.
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2. The transformed triangle is orange in the attachment. It is similar to the original, in that angles have been preserved and lengths are proportional. It is a reflection across the origin and a dilation by a factor of 2. Line slopes have also been preserved. A dilation is NOT a "rigid" transformation.
Answer:
x=14
Step-by-step explanation:
you should set up your problem like this:
5x=3x+28
use order of operations aka PEMDAS to solve
you're answer is 14
Answer:
s=P-b/2
Step-by-step explanation:
P-b=2s
P-b/2=s
Answer:
I'll give you a hint
Step-by-step explanation:
The angles are not supplementary, which means they add up to 180 degrees, they are complementary, which means they add up to 90 degrees
Hope this helps!
Answer:
F = 3x +(2.7×10^7)/x
Step-by-step explanation:
The formulas for area and perimeter of a rectangle can be used to find the desired function.
<h3>Area</h3>
The area of the rectangle will be the product of its dimensions:
A = LW
Using the given values, we have ...
13.5×10^6 = xy
Solving for y gives ...
y = (13.5×10^6)/x
<h3>Perimeter</h3>
The perimeter of the rectangle is the sum of the side lengths:
P = 2(L+W) = 2(x+y)
<h3>Fence length</h3>
The total amount of fence required is the perimeter plus one more section that is x feet long.
F = 2(x +y) +x = 3x +2y
Substituting for y, we have a function of x:
F = 3x +(2.7×10^7)/x
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<em>Additional comment</em>
The length of fence required is minimized for x=3000. The overall size of that fenced area is x=3000 ft by y=4500 ft. Each half is 3000 ft by 2250 ft. Half of the total 18000 ft of fence is used for each of the perpendicular directions: 3x=2y=9000 ft.