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never [62]
2 years ago
7

Complete the latter: 1, 5, 9, 13.

Mathematics
2 answers:
Solnce55 [7]2 years ago
4 0

Answer:

17

Step-by-step explanation:

The answer is 17 because We noticed that 5 is 4 more than 1, 9 is 4 more than 5, and 13 is 4 more than 9. They are all a +4 pattern so you just simply add 4 to 13 which is 13 + 4 + 17 So our answer is 17

MatroZZZ [7]2 years ago
3 0

Answer:

17

Step-by-step explanation:

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Express 0.6 as a fraction.
ollegr [7]

Answer: 3/5

Step-by-step explanation: Using the place value chart, we can see that the decimal 0.6 is 6 tenths. So we can write 0.6 as the fraction 6/10.

Notice however that 6/10 is not in lowest terms.

So we need to divide the numerator and the denominator by the greatest common factor of 6 and 10 which is 2.

So if we divide the numerator and denominator by 2, we get 3/5.

So 0.6 can be written as the fraction 3/5 which is in lowest terms.

Image provided showing the place value chart.

6 0
3 years ago
Read 2 more answers
Dont tell me the Answer but walk me through the steps plz
sveticcg [70]

Answer:

Find the multiplies of 2

7 0
3 years ago
last summer, at camp okey-fun-okey, the ratio of the number of boy campers to girl campers was 8:7. If there were a total of 195
Evgen [1.6K]

The ration of boy campers to total campers is 8:15, and the ratio of girl campers to total campers is 7:15.  Using this information, we can answer this question by setting up proportions.

<u>For boys:</u>

\frac{8}{15} =\frac{x}{195}

<em>*Cross multiply*</em>

15x=1560

<em>*Divide both sides by 15*</em>

x=104

There are 169 boy campers.


<u>For girls:</u>

\frac{7}{15} =\frac{x}{195}

<em>*Cross multiply*</em>

15x=1365

91=x

There are 91 girl campers.


Hope this helps!!

7 0
3 years ago
Read 2 more answers
Bobby has already ran 1 mile on his own, and he expects to run 1 mile during each track practice. How many track practices would
german

Answer:

In order to have ran 33 miles, Bobby would have to attend <em>32 track practices.</em>

Step-by-step explanation:

Solving this problem entails of uncovering the amount of track practices Bobby must attend in order to have ran 33 miles. Start by reading the problem carefully to break down the information provided.

You can see that Bobby has already ran one mile on his own. This is important to remember for later. The problem also states that he expects to run one mile at every track practice.

Setting up an equation will help us solve. Here is how we could set up the equation:

(<em>amount of miles already ran</em> = 1) + (<em>number of track practices</em> = x) = (<em>total miles to run</em> = 33)

1 + x = 33

The equation is now in place. You can solve this, or isolate <em>'x',</em> by using the subtraction property of equality. This means we will subtract one from both sides of the equation, thus isolating the variable.

1 + x = 33

1 - 1 + x = 33 - 1

x = 32

The variable is the only term left on the left side of the equation. This means Bobby must attend track practice <em>32 times</em> in order to have ran 33 miles.

8 0
3 years ago
A $104.000 selling price with $24000 down at 8 1/2% for 25 years results in a monthly payment of
romanna [79]
*******************************************************
(See attached formula)
Loan Principal = 104,000 - 24,000 = 80,000
rate = 8.5 / 1,200  = <span> <span> <span> 0.0070833333 </span> </span> </span>
time = 25 years = 300 months

Monthly Payment = <span> <span> 0.0070833333 </span> + </span><span> <span> [ 0.0070833333 / ((1</span></span><span>.0070833333)^300 -1)) ] *principal
</span>
Monthly Payment = <span>0.0070833333 + </span><span> [ 0.0070833333 / (</span><span> </span> <span> <span> <span> 8.3104129461 </span> </span> </span> -1)] * 80,000
Monthly Payment = 0.0070833333 + [ 0.0070833333 / ( 7.3104129461)] * 80,000
Monthly Payment = (0.0070833333 + <span> <span> <span> 0.00096893750767) * 80,000
</span></span></span>Monthly Payment = <span> <span> <span> 0.00805227080767 </span> </span> </span> * 80,000
Monthly Payment = <span> <span> <span> 644.18

Source:
http://www.1728.org/calcloan.htm

</span></span></span>

3 0
3 years ago
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