Question

Functions f(x) and g(x) are shown below:

Answer 1

We look for the minimum of each function.
 For f (x) = 3x2 + 12x + 16:
 We derive the function:
 f '(x) = 6x + 12
 We match zero:
 6x + 12 = 0
 We clear the value of x:
 x = -12/6
 x = -2
 We substitute the value of x in the equation:
 f (-2) = 3 * (- 2) ^ 2 + 12 * (- 2) + 16
 f (-2) = 4
 For g (x) = 2sin(x-pi):
 From the graph we observe that the minimum value of the function is:
 y = -2
 Answer:
 A function that has the smallest minimum y-value is:
 y = -2