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Over [174]
3 years ago
13

Functions f(x) and g(x) are shown below:

Mathematics
1 answer:
kondor19780726 [428]3 years ago
4 0
We look for the minimum of each function.
 For f (x) = 3x2 + 12x + 16:
 We derive the function:
 f '(x) = 6x + 12
 We match zero:
 6x + 12 = 0
 We clear the value of x:
 x = -12/6
 x = -2
 We substitute the value of x in the equation:
 f (-2) = 3 * (- 2) ^ 2 + 12 * (- 2) + 16
 f (-2) = 4
 For g (x) = 2sin(x-pi):
 From the graph we observe that the minimum value of the function is:
 y = -2
 Answer:
 
A function that has the smallest minimum y-value is:
 
y = -2
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How does the graph of g(x) = <img src="https://tex.z-dn.net/?f=%28x%2B12%29%5E%7B2%7D" id="TexFormula1" title="(x+12)^{2}" alt="
Law Incorporation [45]

Answer:

Horizontal translation of the parent graph

Step-by-step explanation:

<h2><u>Definitions</u>:</h2>

In the <u>vertex form</u> of a quadratic function, f(x) = a(x - h)² + k, where:

  • (h, k) = vertex of the graph
  • <em>a</em>  = determines the width and direction of the graph's opening.

A <u>horizonal translation</u> to the parent graph is given by, y = f(x - h), where:

  • <em>h</em> > 0 ⇒ Horizontal translation of <em>h</em> units to the right
  • <em>h</em> < 0 ⇒ Horizontal translation of |<em>h </em>| units to the left

In the graph of g(x) = (x + 12)², the <u>vertex</u> occurs at point (-12, 0).

While the <u>vertex</u> of the parent graph, f(x) = x² occurs at point, (0, 0).

<h2><u>Answers</u>:</h2>

Since the vertex of g(x) occurs at point, (-12, 0), substituting the value of (<em>h</em>, <em>k </em>) into the vertex form will result into:

g(x) = a(x - h)² + k

g(x) = [x - (-12)]² + 0

g(x) = (x + 12)² + 0

g(x) = (x + 12)²

Therefore, the graph of g(x) = (x + 12)² represents the horizontal translation of the parent graph, f(x) = x², where the graph of g(x) is <em>horizontally</em> translated 12 units to the left.  

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What is the y-intercept?
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The y-intercept is 10.
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Read 2 more answers
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