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3 years ago

What is additive property

Mathematics

1 answer:

Snowcat [4.5K]3 years ago

7 0

Answer and Explanation:

I'm assuming you mean the "Additive property of equality".

The additive property of equality states if the same value amount is added to both sides of an expression or equation, it will remain equal.

Similarly, the additive property of inequalities states if the same value amount is added to both sides of an inequality, it will remain true.

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LaTeX: \frac{4}{5}\times\frac{7}{10}\:=\:4 5 × 7 10 =

Gennadij [26K]

Is that even an actual equation?

7 0

3 years ago

I need the whole solution

ddd [48]

Confused what the question is. Are you looking for the product or the zeroes?

If you are looking for the product, then:

Use foil to get: sec²(1) - sec²(-csc²) -1(1) -1(-csc²)

= sec² + sec²csc² - 1 + csc²

= sec²csc² + sec² + csc² - 1

= sec²csc² + 1 - 1 (NOTE: sec² + csc² = 1 is an identity)

= sec²csc²

Answer: sec²csc²

***************************************************

If you are looking for the zeroes, then:

Using the zero product property, set each factor equal to zero and solve.

First factor:

sec²Θ - 1 = 0

sec²Θ = 1

secΘ = 1, -1

remember that secΘ is $\frac{1}{cos}$

$\frac{1}{cos}$ = 1 $\frac{1}{cos}$ = -1

cross multiply to get:

cosΘ = 1 cosΘ = -1

use the unit circle (or a calculator) to find that Θ = 0 and π

Second factor:

1 - csc²Θ = 0

1 = csc²Θ

1, -1 = cscΘ

remember that cscΘ is $\frac{1}{sin}$

$\frac{1}{sin}$ = 1 $\frac{1}{sin}$ = -1

cross multiply to get:

sinΘ = 1 sinΘ = -1

use the unit circle (or a calculator) to find that Θ = $\frac{\pi}{2}$ and $\frac{3\pi}{2}$

Answer: 0, π, $\frac{\pi}{2}$ , $\frac{3\pi}{2}$

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3 years ago

What is 91/22 in decimal?

Lemur [1.5K]

4.13 (continues) is the answer

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3 years ago

Write 0.896146 to 2 significant figures.

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The correct answer is somewhere

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3 years ago

How much money should be invested at 5% interest, compounded quarterly, so that 7 years later the investment will be worth $5000

vampirchik [111]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$5000\\
P=\textit{original amount deposited}\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, four times}
\end{array}\to &4\\
t=years\to &7
\end{cases}
\\\\\\
5000=P\left(1+\frac{0.05}{4}\right)^{4\cdot 7}\implies 5000=P(1.0125)^{28}\\\\\\ \cfrac{5000}{(1.0125)^{28}}=P$

8 0

3 years ago