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Tresset [83]
3 years ago
8

Maria is training to be a long distance runner. She runs once every day. On the average, each day that Maria has run, she has im

proved her time by 20 seconds. Today she ran for the fifth time. Her time was 10 minutes 48 seconds. What was Maria's running time the first day she ran?
Mathematics
1 answer:
Sav [38]3 years ago
7 0

Answer:

9 mins and 8 secs

Step-by-step explanation:

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Distributive property 54 divided by 8
const2013 [10]
(50÷8)+(4÷8) this is h answer
4 0
3 years ago
Independent Practice
aleksklad [387]

Answer:

A.

2 72 square root of 7

Step-by-step explanation:

Combine the fractions by finding a common denominator.

Exact Form:

2

7

Decimal Form:

0.

¯¯¯¯¯¯¯¯¯¯¯¯

285714

Simplify the expression.

Exact Form:

2

√

7

Decimal Form:

5.29150262

…

8 0
3 years ago
The area of a square is given by x2, where x is the length of one side. Mary's original garden was in the shape of a square. She
Vinil7 [7]

Answer:

128\text{ ft}^{2}

Step-by-step explanation:

We have been given that the area of a square is given by x^2, where x is the length of one side.

Mary's original garden was in the shape of a square. She has decided to double the area of her garden. So the new area of Mary's garden will be 2 times the area of original garden.

We can represent this information in an equation as:

\text{Area of Mary's new garden}=2x^{2}

Therefore, the expression 2x^2 will represent the area of Mary's new garden.

To evaluate the area of new garden, if the side length of Mary's original garden was 8 feet, we will substitute x equals 8 in our expression.

\text{Area of Mary's new garden}=2(8\text{ ft})^{2}

\text{Area of Mary's new garden}=2*64\text{ ft}^{2}

\text{Area of Mary's new garden}=128\text{ ft}^{2}

Therefore, the area of Mary's new garden will be 128 square feet.

4 0
3 years ago
In triangle ΔABC, ∠C is a right angle and CD is the height to
Zina [86]

Answer:

m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha

Step-by-step explanation:

The triangles are drawn below.

CD is perpendicular to AB as CD is height to AB.

Therefore, angles m\angle CDB=m\angle CDA=90°

So, triangles ΔCBD and ΔCAD are right angled triangles.

Now, from the right angled triangle ΔABC,

m\angle A+m\angle B =90\\\alpha+m\angle B=90\\m\angle B=90-\alpha

From ΔCBD,

m\angle CBD is same as m\angle B.

So, m\angle CBD=90-\alpha

m\angle BCD+m\angle BDC =90\\m\angle BCD+90-\alpha=90\\m\angle BCD=\alpha

Now, from ΔCAD,

m\angle CAD is same as m\angle A

So, m\angle CAD=\alpha

m\angle CAD+m\angle ACD =90\\\alpha+m\angle ACD=90\\m\angle ACD=90-\alpha

Hence, the unknown angles of both the triangles are:

m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha

5 0
3 years ago
If ƒ={(5, 1),(6, 2),(7, 3),(8, 1),(9, 7)}, then the range of ƒ is {(1, 5),(2, 6),(3, 7),(1, 8),(7, 9)} {1, 2, 3, 7} {5, 6, 7, 8,
navik [9.2K]

Answer:

{1,2,3,7}

Step-by-step explanation:

The range of a relation is the set of y-values of the ordered pairs.

The given relation is:

ƒ={(5, 1),(6, 2),(7, 3),(8, 1),(9, 7)},

The set of y-values of the given ordered pairs are;

{1,2,3,7}

Therefore the range of y is {1,2,3,7}

5 0
3 years ago
Read 2 more answers
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