Answer:
424 grams CaCl₂
Explanation:
To find the mass of CaCl₂, you need to (1) calculate the moles (using the molarity ratio) and then (2) convert moles to grams (using the molar mass). The final answer should have 3 sig figs to match the given value with the least amount of sig figs.
(Step 1)
Molarity (M) = moles / volume (L)
1.56 M = moles / 2.451 L
3.82 = moles
(Step 2)
Molar Mass (CaCl₂): 40.078 g/mol + 2(35.453 g/mol)
Molar Mass (CaCl₂): 110.984 g/mol
3.82 moles CaCl₂ 110.984 g
---------------------------- x ------------------- = 424 grams CaCl₂
1 mole
Answer:
mole ratio, which is equivalent to a 1;1 mole ratio, to a gram ratio. This means that when the reaction consumes 84.03 g of carbon monoxide, it should theoretically produce 132.03 g of carbon dioxide. Use this gram ratio to calculate the theoretical yield for your reaction.
Explanation:
Answer: The difference between a physical reaction and a chemical reaction is composition. In a chemical reaction, there is a change in the composition of the substances in question; in a physical change there is a difference in the appearance, smell, or simple display of a sample of matter without a change in composition.
Explanation:
Molar mass ( CuSO₄) = 159.609 g/mol
159.609 g ----------------- 6.02 x 10²³ molecules
? g ------------------ 3.36 x 10²³ molecules
mass = ( 3.36 x10²³) x 159.609 / 6.02 x 10²³
mass = 5.36 x 10²⁴ / 6.02 x 10²³
mass = 8.90 g
hope this helps!
