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liq [111]
3 years ago
12

Coal and natural gas are examples of

Chemistry
2 answers:
Alex_Xolod [135]3 years ago
6 0
Coal and natural gas are examples of fossil fuels, I believe!
Yuliya22 [10]3 years ago
3 0

nonrenewable resources!

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Imagine a made-up pol
zheka24 [161]

Answer:

No change to the cation  Add -ide to the anion

Question 1 and .2

Explanation:

6 0
3 years ago
In the reaction between Lithium Sulfate and an excess of Lead (II) Nitrate, how many molecules of Lithium Nitrate can be expecte
siniylev [52]

Answer:

1.46x10^{23}molecules \ LiNO_3

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

Li_2SO_4 + Pb(NO_3)_2 \rightarrow PbSO_4+2LiNO_3

Thus, since lead (II) nitrate is in excess, we can directly compute the moles of lithium nitrate by applying the 1:2 molar ratio between them in the chemical reaction as well as the molar mass of Lithium Sulfate that is 110 g/mol for the stoichiometric shown below factor:

n_{LiNO_3}=13.3gLi_2SO_4*\frac{1molLi_2SO_4}{110gLi_2SO_4} *\frac{2molLiNO_3}{1molLi_2SO_4} =0.242molLiNO_3

Finally, by using the Avogadro's number we are able to compute the molecules:

0.242molLiNO_3*\frac{6.022x10^{23}molecules\ LiNO_3}{1mol}=1.46x10^{23}molecules \ LiNO_3

Best regards.

5 0
4 years ago
Read 2 more answers
3. Calculate the number of atoms needed to balance the following equation:
Ber [7]
Balanced equation: 10 CaCo3 + 20 HCl = 10 CaCl2 + H20 + 15 Co2
3 0
3 years ago
What is technology?
vodomira [7]

Answer:

Any device that contains electronic parts

4 0
3 years ago
On a mission to a newly discovered planet, an astronaut finds chlorine abundances of 13.85 % for 35Cl and 86.15 % for 37Cl. What
topjm [15]

Answer : The atomic mass of chlorine is, 36.723 amu

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

Mass of 35-Cl isotope = 35 amu

Percentage abundance of 35-Cl isotope = 13.85 %

Fractional abundance of 35-Cl isotope = 0.1385

Mass of 37-Cl isotope = 37 amu

Percentage abundance of 37-Cl isotope = 86.15 %

Fractional abundance of 37-Cl isotope = 0.8615

Now put all the given values in above formula, we get:

\text{Average atomic mass }=[(35\times 0.1385)+(37\times 0.8615)]

\text{Average atomic mass }=36.723amu

Therefore, the atomic mass of chlorine is, 36.723 amu

6 0
4 years ago
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