Answer:
Proved
Step-by-step explanation:
To prove that every point in the open interval (0,1) is an interior point of S
This we can prove by contradiction method.
Let, if possible c be a point in the interval which is not an interior point.
Then c has a neighbourhood which contains atleast one point not in (0,1)
Let d be the point which is in neighbourhood of c but not in S(0,1)
Then the points between c and d would be either in (0,1) or not in (0,1)
If out of all points say d1,d2..... we find that dn is a point which is in (0,1) and dn+1 is not in (0,1) however large n is.
Then we find that dn is a boundary point of S
But since S is an open interval there is no boundary point hence we get a contradiction. Our assumption was wrong.
Every point of S=(0, 1) is an interior point of S.
Answer:
It is not correct.
Step-by-step explanation:
If you plug 4 in for x, you get -2*4+5=13. This simplifies to: -8+5=13. This is an untrue statement since -8+5 is actually -3, not 13.
Hope this is helpful! :)
Answer:

Step-by-step explanation:
here's the solution :-
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The reason why the trails must be in quadrant 2 or 3 is because the coordinates start with a negative number. Quadrant 2= (-,+) and quadrant 3= (-,-)
Answer:
y=3x-4
Step-by-step explanation:
Slope intercept form is :
y=mx+b
where m is the slope, and b is the y intercept.
We are given the slope, it is 3. we are also given the y intercept, it is (0,-4). For this form, the 0 in (0,-4) is ignored, and we consider the y intercept to be -4.
So, m is 3, and b is -4. Substitute the values into the equation
y=3x+ -4
y=3x-4
So, the equation in slope intercept form is
y=3x-4