I’m not sure what the question is but I’m just gonna assume that you need the equation: y=1/2x+5
Answer:
<em>x ≥ 2</em>
Step-by-step explanation:
Distribute 8:
8 (3.5x - 2) ≥ 40
28x - 16 ≥ 40
Add 16:
28x ≥ 40 + 16
28x ≥ 56
Divide by 28:
x ≥ 56 ÷ 28
x ≥ 2
Answer:
C.I = 0.7608 ≤ p ≤ 0.8392
Step-by-step explanation:
Given that:
Let consider a random sample n = 400 candidates where 320 residents indicated that they voted for Obama
probability 
= 0.8
Level of significance ∝ = 100 -95%
= 5%
= 0.05
The objective is to develop a 95% confidence interval estimate for the proportion of all Boston residents who voted for Obama.
The confidence internal can be computed as:

where;
=
= 1.960
SO;






= 0.8 - 0.0392 OR 0.8 + 0.0392
= 0.7608 OR 0.8392
Thus; C.I = 0.7608 ≤ p ≤ 0.8392
Answer:
Did you ask a question? I just checked your profile to see if you posted any but i dont see anything except this
Step-by-step explanation: