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3 years ago

15

There are 8 teams playing in the tournament. Each team is scheduled to play every other team once. How many games will be played

during the tournament?
A) 15
B) 21
C) 28
D) 36

2 answers:

Hunter-Best [27]3 years ago

6 0

Answer:

c.) 28

Step-by-step explanation:

I hope this helped. I know it probably doesn't. But I hope you get the question right. And I am sorry if you get it wrong.

alex41 [277]3 years ago

5 0

C) 28

Explanation:
Set it up like a chart of 8 teams (A - H)
Where you list off what team they still have to face

A: B, C, D, E, F, G, H
B: C, D, E, F, G, H
C: D, E, F, G, H
D: E, F, G, H
E: F, G, H
F: G, H
G: H
H: has no one left to fight

Count the total and you’ll get 28

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we will proceed to resolve each case to determine the solution

we have

$y-2x \leq -3$

$y\leq2x-3$

we know that

If an ordered pair is the solution of the inequality, then it must satisfy the inequality.

<u>case a)</u> $(5,-3)$

Substitute the value of x and y in the inequality

$-3\leq2*5-3$

$-3\leq7$ -------> is true

so

The ordered pair $(5,-3)$ is a solution

<u>case b)</u> $(0,-2)$

Substitute the value of x and y in the inequality

$-2\leq2*0-3$

$-2\leq-3$ -------> is False

so

The ordered pair $(0,-2)$ is not a solution

<u>case c)</u> $(-6,-3)$

Substitute the value of x and y in the inequality

$-3\leq2*-6-3$

$-3\leq-15$ -------> is False

so

The ordered pair $(-6,-3)$ is not a solution

<u>case d)</u> $(1,-1)$

Substitute the value of x and y in the inequality

$-1\leq2*1-3$

$-1\leq-1$ -------> is True

so

The ordered pair $(1,-1)$ is a solution

<u>case e)</u> $(7,12)$

Substitute the value of x and y in the inequality

$12\leq2*7-3$

$12\leq11$ -------> is False

so

The ordered pair $(7,12)$ is not a solution

Verify

using a graphing tool

see the attached figure

the solution is the shaded area below the line

The points A and D lies on the shaded area, therefore the ordered pairs A and D are solution of the inequality

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