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vitfil [10]
3 years ago
9

A circle have a diameter of 18 meters. What is its

Mathematics
1 answer:
Sergio [31]3 years ago
3 0

Answer:

A. 56.54867 rounded to 56.56

Step-by-step explanation:

18/2=9

r=9

C=2πr=2·π·

C=2(3.14)(9)

9≈56.54867

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Please Help me answer all 4 questions with a full explanation so I can solve the rest on my own.
Nata [24]

\\ \rm\Rrightarrow (2x^2)^3.2yx^0=8x^6.2y=16x^6y

\\ \rm\Rrightarrow (2x^4y^3)^3.2x^4y^4=8x^{12}y^6.2x^4y^4=16x^{16}y^{10}

\\ \rm\Rrightarrow (m^3n^0(2m^3n^2)^4)^2=(m^316m^{12}n^8)^2=(16m^{15}n^8)^2=256m^{30}n^{16}

\\ \rm\Rrightarrow (2xy^3)^2.2x^2y^0=4x^2y^6.2x^2=8x^4y^6

6 0
2 years ago
Solve. t - (- 10) = 9
Gekata [30.6K]
T - ( - 10) = 9
t + 10 = 9
t = 9 - 10
t = -1

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Answer: t = -1
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5 0
3 years ago
Read 2 more answers
Ask Your Teacher Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified
Igoryamba

Answer:

V=15.44

Step-by-step explanation:

We have a formula

V=\int^{π/3}_{-π/3} A(x) dx ,

where A(x) calculate as  cross sectional.

We have:

Inner radius: 5 + sec(x) - 5= sec(x)  

Outer radius: 7 - 5=2, we get

A(x)=π 2²- π· sec²(x)

A(x)=π(4-sec²(x))

Therefore, we calculate the volume V, and we get

V=\int^{π/3}_{-π/3} A(x) dx

V=\int^{π/3}_{-π/3} π(4-sec²(x)) dx

V=[ π(4x-tan(x)]^{π/3}_{-π/3}

V=π·(8π/3-2√3)

V=15.44

We use a site geogebra.org to plot the graph.

5 0
4 years ago
Consider the two functions:
Mademuasel [1]

Answer:

  g(0) > f(0)

Step-by-step explanation:

Evaluate the functions at the point of interest: x=0.

  g(0) = 20·1.5^0 = 20·1 = 20

  f(0) = -40 . . . . from the table

Since 20 > -40, we conclude ...

  g(0) > f(0)

8 0
3 years ago
I will give you 5 stars and a heart!
Artemon [7]
So from these given details will be right choice A. sure because given that 1 unit cube = 1 inch so from this result that 48 unit cubes = 48 cubic inches 

hope this will help you 
7 0
3 years ago
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