Answer:
- 10 and 60
Step-by-step explanation:
1
To evaluate f(- 2) substitute x = - 2 into f(x)
f(- 2) = (3 × - 2) - 4 = - 6 - 4 = - 10
2
To evaluate f(8) substitute x = 8 into f(x)
f(8) = 8² - 4 = 64 - 4 = 60
Answer:-7d=13
7d=-13
d=-13/7
Step-by-step explanation:
Hope this helps!
Make sure to apply same operations to both sides.
Answer:
0.036
Step-by-step explanation:
<em>The </em><em>diameter</em><em> </em><em>is </em><em>0</em><em>.</em><em>6</em><em>/</em><em>2</em><em>,</em><em> </em><em>which </em><em>is </em><em>0</em><em>.</em><em>3</em><em> </em><em>and </em><em>your </em><em>radius </em><em>is </em><em>0</em><em>.</em><em>3</em><em>.</em>
<em>on </em><em>your </em><em>calculator</em><em> </em><em>,</em><em> </em><em>you'll</em><em> </em><em>press </em><em>4</em><em>/</em><em>3</em><em> </em><em>×</em><em> </em><em>0</em><em>.</em><em>3</em><em>^</em><em>3</em>
<em>which </em><em>is </em><em>equals </em><em>to </em><em>0</em><em>.</em><em>0</em><em>3</em><em>6</em><em>π</em>
Answer:
4/3 or 1 1/3
Step-by-step explanation:
So if y = 6, when x = 2/3. Then, x would equal 1 and 1/3, because 12 is twice the amount of 6, so you'd also multiply 2/3 by 2.
(To multiply a whole number by a fraction, first multiply the whole number by the numerator and then divide that by the denominator. For example: 2 × 2 = 4, since you can't really divide 4 by 3 it would stay as is, but you can turn it to a mixed number. 4/3 is the same as 1 whole and an extra 1/3, or in other words 1 1/3).
Hope this helped :)
Answer:
Part a) The slant height is 
Part b) The lateral area is equal to 
Step-by-step explanation:
we know that
The lateral area of a right pyramid with a regular hexagon base is equal to the area of its six triangular faces
so
![LA=6[\frac{1}{2}(b)(l)]](https://tex.z-dn.net/?f=LA%3D6%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28l%29%5D)
where
b is the length side of the hexagon
l is the slant height of the pyramid
Part a) Find the slant height l
Applying the Pythagoras Theorem
where
h is the height of the pyramid
a is the apothem
we have
substitute
Part b) Find the lateral area
we have
substitute the values
![LA=6[\frac{1}{2}(6)(3\sqrt{2})]=54\sqrt{2}\ units^{2}](https://tex.z-dn.net/?f=LA%3D6%5B%5Cfrac%7B1%7D%7B2%7D%286%29%283%5Csqrt%7B2%7D%29%5D%3D54%5Csqrt%7B2%7D%5C%20units%5E%7B2%7D)
