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3 years ago

The depth of a lake is 15.8 m.

Mathematics

2 answers:

Vesnalui [34]3 years ago

7 0

Answer:

16 meters

Step-by-step explanation:

lesya692 [45]3 years ago

4 0

Answer:

16 m

Step-by-step explanation:

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Anita has a cellphone contract that costs her R100 per month plus 85 cents per peak time SMS,and 25 cents per off-peak time SMS.

algol [13]

Answer:

Anita's monthly bill will be $164.25.

Step-by-step explanation:

Since Anita has a cellphone contract that costs her R100 per month plus 85 cents per peak time SMS, and 25 cents per off-peak time SMS, if she sends 45 SMSs during peak time and 105 SMSs during off-peak time In a month To determine what will her monthly bill come to, the following calculation must be performed:

100 + (0.85 x 45) + (0.25 x 105) = X

100 + 38.25 + 26.25 = X

138.25 + 26.25 = X

164.25 = X

Therefore, her monthly bill will be $ 164.25.

6 0

3 years ago

Can someone show me step by step on how to solve this, I'd very much appreciate the help. In the figure below, what is the value

klemol [59]

Answer:

Step-by-step explanation:

According to the Exterior Angle Theorem, the exterior angle is equal to the sum of the interior angles opposite from the exterior angle. In other words:

$68+x=100$

Solve for x. Therefore:

$m\angle x=32^\circ$

Our answer is D.

5 0

3 years ago

Read 2 more answers

Suppose that the population of the scores of all high school seniors who took the SAT Math (SAT-M) test this year follows a Norm

Vlad1618 [11]

Answer:

Confidence = $1-\alpha=1-0.01=0.99$

And then the confidence level would be given by 99%

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma)$

The distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\bar x =512$ represent the sample mean

$\sigma=100$ represent the population standard deviation

n= 100 sample size selected.

The confidence interval is given by this formula:

$\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$ (1)

The marginof error for this case is given by Me=25.76. And we know that the formula for the margin of error is given by:

$Me=z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

$25.76=z_{\alpha/2} \frac{100}{\sqrt{100}}$

And we can find the critical value $z_{\alpha/2}$ like this:

$z_{\alpha/2}=\frac{25.76(\sqrt{100})}{100}=2.576$

And we know that on the right tail of the z score =2.576 we have $\alpha/2$ of the total area. We can find the area on the right of the z score using this excel code:

"=1-NORM.DIST(2.576,0,1,TRUE)" or using a table of the normal standard distribution, and we got 0.004998= $\alpha/2$ , so then $\alpha=0.00498*2=0.009995 \approx 0.01$ , and then we can find the confidence like this: