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3 years ago

What are the steps for using integer tiles to evaluate the expression 45 divided by 15

Mathematics

2 answers:

kogti [31]3 years ago

7 0

Answer: B.Start with 45 tiles and separate them into 15 same-sized groups.

Step-by-step explanation:

To evaluate 45 divided by 15 using integer tiles .

Here dividend = 45

Divisor =15

First we need to start with the dividend number, therefore we have to start with 45 tiles .

For the second step we need to separate them into same sized group and the size of the group must be same as the divisor.

Thus, we need to separate 45 tiles into 15 same-sized groups, we will get 3 groups which will be the answer.

Therefore, B is the right option.

Goryan [66]3 years ago

6 0

The answer is B. Hope you get it.

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A computer programming team has 13 members. a. How many ways can a group of seven be chosen to work on a project? b. Suppose sev

Julli [10]

Answer:

1716 ;

700 ;

1715 ;

658 ;

1254 ;

792

Step-by-step explanation:

Given that :

Number of members (n) = 13

a. How many ways can a group of seven be chosen to work on a project?

13C7:

Recall :

nCr = n! ÷ (n-r)! r!

13C7 = 13! ÷ (13 - 7)!7!

= 13! ÷ 6! 7!

(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)

1235520 / 720

= 1716

b. Suppose seven team members are women and six are men.

Men = 6 ; women = 7

(i) How many groups of seven can be chosen that contain four women and three men?

(7C4) * (6C3)

Using calculator :

7C4 = 35

6C3 = 20

(35 * 20) = 700

(ii) How many groups of seven can be chosen that contain at least one man?

13C7 - 7C7

7C7 = only women

13C7 = 1716

7C7 = 1

1716 - 1 = 1715

(iii) How many groups of seven can be chosen that contain at most three women?

(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)

Using calculator :

(15 * 35) + (6 * 21) + (1 * 7)

525 + 126 + 7

= 658

c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?

(First in second out) + (second in first out) + (both out)

13 - 2 = 11

11C6 + 11C6 + 11C7

Using calculator :

462 + 462 + 330

= 1254

d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?

Number of ways with both in the group = 11C5

Number of ways with both out of the group = 11C7

11C5 + 11C7

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So,

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