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3 years ago

A bakery sold a total of 120 cupcakes in a day, and 66 of them were mocha flavored.

Mathematics

2 answers:

Verdich [7]3 years ago

3 0

Answer:

55%

Step-by-step explanation:

55% of the cupcakes were mocha flavored.

sveticcg [70]3 years ago

3 0

55% of the cupcakes where mocha flavored hope this helps u

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Step-by-step explanation:

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3 years ago

which of the following statements about perpendicular lines is true? a. perpendicular lines have a constant distance between the

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4 years ago

Use the function below to find F(3). <br><br> F(x) = 4(1/3)^x

aalyn [17]

Answer:

4/27

Step-by-step explanation:

F(x) = 4(1/3)^x

Let x =3

F(3) = 4(1/3)^3

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3 years ago

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3 years ago

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The ability to find a job after graduation is very important to GSU students as it is to the students at most colleges and unive

gtnhenbr [62]

Answer: (0.8468, 0.8764)

Step-by-step explanation:

Formula to find the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where $\hat{p}$ = sample proportion.

z* = Critical value

n= Sample size.

Let p be the true proportion of GSU Juniors who believe that they will, immediately, be employed after graduation.

Given : Sample size = 3597

Number of students believe that they will find a job immediately after graduation= 3099

Then, $\hat{p}=\dfrac{3099}{3597}\approx0.8616$

We know that , Critical value for 99% confidence interval = z*=2.576 (By z-table)

The 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation will be

$0.8616\pm(2.576)\sqrt{\dfrac{0.8616(1-0.8616)}{3597}}$

$0.8616\pm (2.576)\sqrt{0.0000331513594662}$

$\approx0.8616\pm0.0148\\\\=(0.8616-0.0148,\ 0.8616+0.0148)=(0.8468,\ 0.8764)$

Hence, the 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation. = (0.8468, 0.8764)

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3 years ago