Solve: 6yd. 9ft. 4in × 2

Mathematics

2 answers:

kondor19780726 [428]3 years ago

6 0

Answer:

Step-by-step explanation:

prisoha [69]3 years ago

4 0

328 inches . . . . . . . . . . . .. . . . . . . . . . . .27.3 feet

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Please please please help!! i need this asap and i have no where else to go!

nadezda [96]

1   1   1       2
2 -3   1 -11 -2R1 + R2 → R2
-1 2 -1 8 R1 + R3 → R3

1 1 1 2
0 -5 -1   -15    R2 ⇔ R3
0 3 0    10

1 1 1 2
0 3 0     10    -R3
0   -5   -1 -15

1 1 1 2
0 3 0     10    1/3 R2
0    5    1    15

1 1 1 2    -R2 + R1
0 1 0     10/3    -5R2 + R3
0    5    1    15

1 0 1 -4/3
0 1 0     10/3    -R3 + R1
0    0    1     -5/3

1 0 0    1/3
0 1 0     10/3
0    0    1     -5/3

Therefore, x = 1/3, y = 10/3, z = -5/3

7 0

2 years ago

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Help with math homework pls!

Svetach [21]

the correct answer is a^6

5 0

3 years ago

ok so if Tony logs-in 10 hours of gaming a day and his gf Shara says if he doesn't get a job she will leave him for Dave.. now h

puteri [66]

Answer:

10 hours

Step-by-step explanation:

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5 0

2 years ago

Consider the parabola given by the equation: f(x) = 4x² - 6x - 8 Find the following for this parabola: A) The vertex: Preview B)

jeyben [28]

Answer:

The vertex: $(\frac{3}{4},-\frac{41}{4} )$

The vertical intercept is: $y=-8$

The coordinates of the two intercepts of the parabola are $(\frac{3+\sqrt{41} }{4} , 0)$ and $(\frac{3-\sqrt{41} }{4} , 0)$

Step-by-step explanation:

To find the vertex of the parabola $4x^2-6x-8$ you need to:

1. Find the coefficients a, b, and c of the parabola equation

$a=4, b=-6, \:and \:c=-8$

2. You can apply this formula to find x-coordinate of the vertex

$x=-\frac{b}{2a}$ , so

$x=-\frac{-6}{2\cdot 4}\\x=\frac{3}{4}$

3. To find the y-coordinate of the vertex you use the parabola equation and x-coordinate of the vertex ( $f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c$ )