Question

Let h(x) = x*2 + kw - 8. If h(-1) = -5, what is the value of h(4)? Help

Answer 1

Answer:

h(4) = 0

Step-by-step explanation:

GIVEN :-

• A quadratic function h(x) = x² + kx - 8
• h(-1) = -5

TO FIND :-

• Value of h(4)

SOLUTION :-

To find the value of h(4) , you need to find 'k' first by using the given facts.

$h(-1) = (-1)^2 + k(-1) - 8 = -5$

$=> 1 - k - 8 = -5$

$=> -k - 7 = -5$

• Add both the sides by 7.

$=> -k - 7 + 7 = -5 + 7$

$=> -k = 2$

• Multiply both the sides by -1.

$=> -k(-1) = 2(-1)$

$=> k = -2$

Putting the value of k,

$h(4) = (4)^2 + (-2)(4) - 8$

       $= 16 - 8 - 8$

       $= 16 - 16$

       $= 0$

Answer 2

Answer:

h(4) = 0

Step-by-step explanation:

Hoping its ' kx '

$h(x) = x^2 + kx -8 \\\\h(-1) = (-1)^2 + k(-1) - 8\\\\-5 = 1 - k -8\\\\-5 = -k -7\\\\-5 + 7 = -k\\\\2 = -k\\-2 = k$

Now we have k = -2. We will find h(4).

$h(4) = (4)^2 + (-2)(4) - 8 = 16 -8 - 8 = 0$