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docker41 [41]
2 years ago
10

Pls help me thank you

Mathematics
2 answers:
DanielleElmas [232]2 years ago
8 0

Answer:

390m^2

Step-by-step explanation:

The Surface Area of a triangular prism is L(s1 + s2 + s3) + 2*base area

a = 5m

b = 12m

c = 13m

L = 11m

First, we need to find the base area...

base area = (a*b)/2

(5*12)/2 = 30 m^2

Next, find the surface area

A = 11(5 + 12 +13) + 2*30 = 390 m^2

PLEASE RATE!! I hope this helps!!

If you have any questions comment below

BaLLatris [955]2 years ago
3 0

Answer:

373 in

Step-by-step explanation:

I hope this is right and it helps you!

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4/3x + 1/6x = 36 (solve for x please help I have no idea what it is!!!!!!!
ElenaW [278]

Answer:

x = 24

Step-by-step explanation:

\frac{4}{3}x + \frac{1}{6}x = 36

Make the denominator the same by multiplying the first fraction by 2 to make both denominators 6.

\frac{8}{6}x + \frac{1}{6}x = 36

Now we can calculate the numerators and keep the denominators the same.

\frac{9}{6}x = 36

Find x.

\frac{6}{6}x = \frac{6}{9} × 36

x = 24

7 0
3 years ago
Enter the equation of the line in slope-intercept form.
nordsb [41]

Answer:

y=3x

Step-by-step explanation:

8 0
3 years ago
Please guys i really need your help and please explain how you got it please
lina2011 [118]
The answer would be C because in order to find the area of a figure, you would need to multiply its height by its width. finding the area of a figure is the same as finding how many units are in a figure. because this is a square and all the sides are equal, by counting the total number of units, you can find the area.
5 0
3 years ago
A right pyramid with a regular hexagon base has a height of 3 units If a side of the hexagon is 6 units long, then the apothem i
Setler79 [48]

Answer:

Part a) The slant height is 3\sqrt{2}\ units

Part b) The lateral area is equal to 54\sqrt{2}\ units^{2}

Step-by-step explanation:

we know that

The lateral area of a right pyramid with a regular hexagon base is equal to the area of its six triangular faces

so

LA=6[\frac{1}{2}(b)(l)]

where

b is the length side of the hexagon

l is the slant height of the pyramid

Part a) Find the slant height l

Applying the Pythagoras Theorem

l^{2}=h^{2} +a^{2}

where

h is the height of the pyramid

a is the apothem

we have

h=3\ units

a=3\ units

substitute

l^{2}=3^{2} +3^{2}

l^{2}=18

l=3\sqrt{2}\ units

Part b) Find the lateral area

LA=6[\frac{1}{2}(b)(l)]

we have

b=6\ units

l=3\sqrt{2}\ units

substitute the values

LA=6[\frac{1}{2}(6)(3\sqrt{2})]=54\sqrt{2}\ units^{2}

3 0
3 years ago
Read 2 more answers
3x^2 + 2x-4 = 0 help
igomit [66]

Answer:

I dont know

Step-by-step explanation:

how to answer that

5 0
3 years ago
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