Answer:
390m^2
Step-by-step explanation:
The Surface Area of a triangular prism is L(s1 + s2 + s3) + 2*base area
a = 5m
b = 12m
c = 13m
L = 11m
First, we need to find the base area...
base area = (a*b)/2
(5*12)/2 = 30 m^2
Next, find the surface area
A = 11(5 + 12 +13) + 2*30 = 390 m^2
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5 1/3 x 2 3/4= 3/4 5 x 2 = 10
Multiply fractions 1/3 x 3/4= 3/4
tan(θ) = 0, 0.577, -0.577
3tan³(θ) - tan(θ) = 0
tan(θ)(3tan²(θ) - 1) = 0
tan(θ) = 0
tan²(θ) = ⅓ tan(θ) = +/- sqrt(⅓)
tan(θ) = 0, sqrt(⅓), -sqrt(⅓)
To find θ values, domain is required
147,000N
A1= 2m^2
A2= 0.2m^2
F2= 14,700N
Required
F1, the applied force
Applying the formula
F1/A1= F2/A2
substute
F1/2=14700/0.2
2*14700= F1*0.2
29400= F1*0.2
F1= 29400/0.2
F1=147,000N
Hence, the applied force is 147,000N
