Find the perimeter and area
1 answer:
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Step-by-step explanation:
Angles in the same segment. The angles at the circumference subtended by the same arc are equal. More simply, angles in the same segment are equal.
Picture 1 a° = a° they are the same
Picture 2 p= 52° q= 40° Angles in the same segment are equal. if they ask you to calculate you just show both angles p= 52 and q=40.
Picture 3 + 4 Let the obtuse angle MOQ = 2x.
Using the circle theorem, the angle at the centre is twice the angle at the circumference.
Therefore picture 4 tells us and proves;
Angle MNQ = x and angle MPQ = x.
Picture 5
A cyclic quadrilateral is a quadrilateral drawn inside a circle. Every corner of the quadrilateral must touch the circumference of the circle.
The second shape is not a cyclic quadrilateral. One corner does not touch the circumference.
Picture 6
The opposite angles in a cyclic quadrilateral add up to 180°.
a + c = 180°
b + d = 180°
Picture 7
Example
Calculate the angles a and b.
The opposite angles in a cyclic quadrilateral add up to 180°.
This is a picture that couldn't be added but has a quadrilateral occupying half the triangle consisting of 3 arcs the middle one was 140 and proved part of one triangle. The x (a) missing angle showed below a = 180-60 = 120 °
So hopefully this will help you remember the format here for quadrilateral shapes within a circle.
b = 180 - 140 = 40°
a = 180 - 60 = 120°
Answer:
The probability of selecting the color of ball that you just selected(a red ball) is
Step-by-step explanation:
From the question we are told that
The total number of colored balls is n = 10
The number of red balls is r = 2 red
The number of white ball is w = 4
The number of blue balls is b = 4
The number of balls to be selected is N = 2 balls
The cost of playing picking a ball is c = $10
The winnings is
Here P(A) is the probability of obtaining the exact sequence of result and from the question it is P(A) = 0.10
Generally my price according to the question is
=>
Let assume we selected a red ball
Generally the probability of selecting a red ball is mathematically represented as