Write 6600 as a product of its prime factors. (show your working out)
1 answer:
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First keep in mind that the given value is negative and that it is greater than or equal to whatever '<em>v</em>' is.
When solving for a variable in any equation, you do something to both sides in order to keep it equal. Here, <em>v</em> is being subtracted by 1.9; therefore we can add 1.9 to both sides in order to isolate <em />the variable.
Despite not needing a value for the question, it is worth noting that since this is an inequality, <em>v </em>can be any value from -6.4 to ∞ in order to make it true.
When solving for a variable in any equation, you do something to both sides in order to keep it equal. Here, <em>v</em> is being subtracted by 1.9; therefore we can add 1.9 to both sides in order to isolate <em />the variable.
Despite not needing a value for the question, it is worth noting that since this is an inequality, <em>v </em>can be any value from -6.4 to ∞ in order to make it true.
Given the next quadratic function:
to sketch its graph, first, we need to find its vertex. The x-coordinate of the vertex is found as follows:
where <em>a</em> and <em>b</em> are the first two coefficients of the quadratic function. Substituting with a = 2 and b = 3, we get:
The y-coordinate of the vertex is found by substituting the x-coordinate in the quadratic function, as follows:
The factorization indicates that the curve crosses the x-axis at the points (-2, 0) and (1/2, 0). We also know that the curve crosses the y-axis at (0,-2). Connecting these points and the vertex (-0.75, -3.125) with a U-shaped curve, we get:
