For the given triangles:
There are 3 pairs of congruent angles
the triangles can not be proved using the congruent angles
the congruent angles used to prove the similarity of the triangles
So, the answer will be:
For the given triangle, we can not prove they are congruent.
Step-by-step explanation:
We want to graph:
![f(x) =\log_{5}(x - 3)](https://tex.z-dn.net/?f=f%28x%29%20%3D%5Clog_%7B5%7D%28x%20-%203%29%20)
We first graph the parent function
![g(x) =\log_{5}(x)](https://tex.z-dn.net/?f=g%28x%29%20%3D%5Clog_%7B5%7D%28x%29%20)
This parent function has x-intercept at (1,0) and it is asymptotic to the y-axis.
We then shift the graph of the parent function 3 units right, to obtain the graph of
![f(x) =\log_{5}(x - 3)](https://tex.z-dn.net/?f=f%28x%29%20%3D%5Clog_%7B5%7D%28x%20-%203%29%20)
The new x-intercept will be (4,0) and vertical asymptote will now be x=3.
See attachment.
Answer: 25 computers will be selected
Step-by-step explanation:
Where: Z -value at 95% confidence = 1.96; SD = Standard deviation = 10 minutes; N = Sample size; Margin error = 4 minutesSubstituting;4 = 1.96*10/Sqrt (N)Sqrt (N) = (1.96*10)/4 = 4.9N = 4.9^2 = 24.01 ≈ 25
Hello from MrBillDoesMath!
Answer:
d>4
Discussion:
I understand the question is asking us to solve for "d" in the inequality:
d + 2 > 6 => subtract 2 from both sides
d + 2 -2 > 6 - 2 => as 2 - 2 = 0
d > 6 -2 = 4
If I have misunderstood the question, please tell me.
Thank you,
MrB
Answer: 16.91°
Step-by-step explanation:
1. You can draw a right triangle as you can see in the figure attached.
2. Then you can calculate the angle of elevation (α) as following:
![\alpha=arcsin(\frac{opposite}{hypotenuse})](https://tex.z-dn.net/?f=%5Calpha%3Darcsin%28%5Cfrac%7Bopposite%7D%7Bhypotenuse%7D%29)
Where:
![opposite=32\\hypotenuse=110](https://tex.z-dn.net/?f=opposite%3D32%5C%5Chypotenuse%3D110)
3. Now you must substitute these values. Then, the angle of elevation is:
![\alpha=arcsin(\frac{32}{110})](https://tex.z-dn.net/?f=%5Calpha%3Darcsin%28%5Cfrac%7B32%7D%7B110%7D%29)
![\alpha=16.91\°](https://tex.z-dn.net/?f=%5Calpha%3D16.91%5C%C2%B0)