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3 years ago

Find the interior angle on a regular polygon with 45 sides...

Mathematics

1 answer:

PolarNik [594]3 years ago

3 0

The exterior angles sum to 360º. Let x be the measure of each exterior angle. Then

45x = 360º ==> x = 8º

Then each interior angle (which is supplementary to an exterior angle) has measure (180 - x)º, so they have measure 172º.

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Find the missing side length. Show all work.<br> first right answer with right work gets 500 points

leva [86]

Answer:

$x=14 \tan 61^{\circ}$

Step-by-step explanation:

$\tan 61^{\circ}=\frac{x}{14} \\ \\ x=14 \tan 61^{\circ}$

4 0

1 year ago

Find the point of intersection (if any) of the following pairs of lines: a) x – 2y +1=0 2x + 3y – 7 = 0 b) x-2y+11=0 -x+2y-13 =

pychu [463]

Answer:

a) (11/7, 9/7)

b) There's no point of intersection

Step-by-step explanation:

a) x - 2y + 1 = 0

2x + 3y - 7 = 0

To find the point of intersection, we need to solve the system of equations and the result will be the point of intersection (x,y)

$x-2y+1=0\\x= 2y-1$

Now we substitute x in the second equation:

$2x+3y-7=0\\2(2y-1)+3y-7=0\\4y-2+3y-7=0\\7y-9=0\\y=9/7$

Now we substitute y in our first equation.

$x-2y+1=0\\x-2(9/7)+1=0\\x-18/7+1=0\\x=18/7-1\\x=11/7$ .

The point of intersection is (11/7, 9/7)

b) x -2y +11 =0

-x + 2y - 13 =0

We are going to follow the same procedure:

$x-2y+11=0\\x=2y-11$

$-(2y-11)+2y-13=0\\-2y+11+2y-13=0\\0y=2\\0=2$

Since this system of equations doesn't have a solution, the system has no point of intersection.

5 0

3 years ago

The different of anumber and 12

Llana [10]

Five divided by the difference of a number and 12 equals the quotiene of 10 and the sum of the number and five

3 0

3 years ago

The position function for a free-falling object is s(t) = -16t^2 + vt +5. A ball is thrown upward from the top of a 400-foot bui

mixer [17]

Answer:

6.21 seconds

Step-by-step explanation:

The position function of a free-falling object is,

$s(t) = -16t^2+v_0t+s_0$

Where,

$s_0$ = initial height of the object,

$v_0$ = initial velocity of the object,

Here,

$s_0=400\text{ feet}$

$v_0=35\text{ feet per sec}$

Hence, the height of the ball after t seconds,

$s(t)=-16t^2+35t+400$

When s(t) = 0,

$\implies -16t^2+35t+400=0$

$t=\frac{-35\pm \sqrt{35^2-4\times -16\times 400}}{2\times -16}$

$t=\frac{-35\pm \sqrt{1225+25600}}{-32}$

$\implies t\approx -4.02\text{ or }t\approx 6.21$

∵ Time cannot be negative,

Hence, after 6.21 seconds the ball will reach the ground.

4 0

3 years ago

Find the amount and the compound interest on 62500 for1*1/2 years at 8% compounded half-yearly

Anettt [7]

principal (p)=62500,Time (T)=1.5 years,Rate (R)=8% Ammount=p (1+R÷100) =62500 × 1.1664 =72900 again, compound interest = p(1+R÷100)-1=62500×0.1664 = 10400

3 0

2 years ago