It gives me adds that i cant skip the keeps me here

Maura runs 5 miles in 1.25 hours. Ava runs 3 miles in 50 minutes or 0.83¯ hour. Who runs faster?

kenny6666 [7]

Answer:

║⊕║∵°·∵∴Hello :)∴∵·°∵∴║⊕║

Your answer should be:

Maura runs faster.

Step-by-step explanation:

I hope this helped!

Brainliest appreciated

8 0

2 years ago

Using this distribution, find the probability

kaheart [24]

Answer:

P = 0.3

Step-by-step explanation:

Here, we are to use the probability distribution in the table to calculate the probability that a children has 4 or more shoes in his or her closet

When we say 4 or more, what we mean by this is that the teenager has 4 shoes or 5 shoes

In probability expressions, when we use the term ‘or’ we are simply talking about adding the terms involved

So what we can do here is to add the probability that the teenager has 4 shoes to the probability that the teenager has five shoes

From the table that would be; 0.1 + 0.2 = 0.3

6 0

3 years ago

Which set represents the range of the function shown? {(8, 2), (6, 5), (4, 7), (11, −2)}

kakasveta [241]

The second numbers in each of the ordered pairs is the range

3 0

3 years ago

Geometry help please!!

Nostrana [21]

Answer: 13

Step-by-step explanation:

Equilateral triangle means that all sides are equal

Soo

3x + 1 must be equal to 5x - 9

3x + 1 = 5x - 9

-2x = -10

x = 5

Substitute x as 5 into either side value

3(5) + 1 = 15 + 1 = 16

So, all sides equal 16

Which means that y + 3 also equals 16

y + 3 = 16

y = 13

7 0

2 years ago

The height of a ball thrown into the air after t seconds have elapsed is h = −16t2 + 40t + 6 feet. What is the first time, t, wh

sp2606 [1]

<h3>The first time when the ball will reach a height of 20 feet is 0.42 seconds</h3>

Solution:

Given that,

The height of a ball thrown into the air after t seconds have elapsed is:

$h = -16t^2 + 40t + 6$

What is the first time, t, when the ball will reach a height of 20 feet?

Substitute h = 20

$20 = -16t^2 + 40t + 6\\\\-16t^2 + 40t + 6 -20 = 0\\\\-16t^2 + 40t -14 = 0\\\\16t^2 -40t + 14 = 0\\\\8t^2 -20t + 7=0$

Solve by quadractic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=8,\:b=-20,\:c=7$

$t = \frac{-\left(-20\right)\pm \sqrt{\left(-20\right)^2-4\cdot \:8\cdot \:7}}{2\cdot \:8}\\\\t = \frac{20 \pm \sqrt{176}}{16}\\\\t = \frac{20 \pm 4\sqrt{11}}{16}\\\\t = \frac{ 5 \pm \sqrt{11}}{4}\\\\We\ have\ two\ solutions\\\\ t=2.07915, \:t=0.42084$

Rounding off we get,

t = 2.08 , t = 0.42

Thus the first time when the ball will reach a height of 20 feet is 0.42 seconds

4 0

3 years ago