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natima [27]
3 years ago
15

Hi please help i’ll give brain

Mathematics
1 answer:
Cloud [144]3 years ago
8 0

Answer:

The GCF is going to be 30

Step-by-step explanation:

This Is how I find the GCF of 2 numbers. I find the prime factorization first, then I find the common factors and multiply them. Here

The prime factorization of 21, 2 × 3 × 3 × 5= 90

The prime factorization of 28, 2 × 3 × 5 × 7 = 210

The common factors are, 2, 3, and 5. We multiply those to get the GCF.

2 × 3 × 5 = 30

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Answer:

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Step-by-step explanation:

Linearity condition is :  <em>NOT MET </em>

The equal variance condition is : <em>NOT MET</em>

The 10% condition :<em> Does not need to be checked for multiple linear regression </em>

The success failure condition : <em>Does not need to be checked for multiple linear regression</em>

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3 years ago
Geometry please help me!!!!
Oliga [24]

Answer:

Step-by-step explanation:

8 0
2 years ago
If any human being adores math pls help me with this!!!
Scilla [17]
First box is 100 second is 4 third is 1500 4th box is 60 and last box is 1560
4 0
3 years ago
2. The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability th
coldgirl [10]

Answer:

0.30

Step-by-step explanation:

Probability of stopping at first signal = 0.36 ;

P(stop 1) = P(x) = 0.36

Probability of stopping at second signal = 0.54;

P(stop 2) = P(y) = 0.54

Probability of stopping at atleast one of the two signals:

P(x U y) = 0.6

Stopping at both signals :

P(xny) = p(x) + p(y) - p(xUy)

P(xny) = 0.36 + 0.54 - 0.6

P(xny) = 0.3

Stopping at x but not y

P(x n y') = P(x) - P(xny) = 0.36 - 0.3 = 0.06

Stopping at y but not x

P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24

Probability of stopping at exactly 1 signal :

P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30

8 0
3 years ago
Please help as soon as possible 50 points
Morgarella [4.7K]

Answer:

the answer is d. 4x²+x-6

Step-by-step explanation:

In order to combine the fractions, they need to have the same denominator.

So, multiply each of their numerators by the denominator they need to be equivalent.

This would look like this:

3x/x+3 --> 3x(x)/x(x+3)        ---simplify this as--> 3x²/x(x+3)

x-2/x  --> (x-2)(x+3)/x(x+3)  ---simplify this as --> x²+x - 6/x(x+3)

3x                    3x(x)                                     x-2                   (x-2)(x+3)

-----      --->        -----                 and             --------   --->           ---------

x+3                   x(x+3)                                    x                        x(x+3)

now that both fractions have the same denominator, we can add their numerators.

3x² + x²+x-6 = 4x²+x -6

This should now look like this:

4x²+x -6

-------------

x(x+3)

8 0
2 years ago
Read 2 more answers
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