Answer:
Step-by-step explanation:
Radius = r = 3 in.
Height = h = 2 in.
<u>Volume:</u>
![\sf Volume \ of \ the \ cylinder = \pi r^2 h\\\\V = (3.14)(3)^2(2)\\\\V =(3.14)(9)(2)\\\\V = (3.14)(18)\\\\V = 56.5 \ in.^3\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20Volume%20%5C%20of%20%5C%20the%20%5C%20cylinder%20%3D%20%5Cpi%20r%5E2%20h%5C%5C%5C%5CV%20%3D%20%283.14%29%283%29%5E2%282%29%5C%5C%5C%5CV%20%3D%283.14%29%289%29%282%29%5C%5C%5C%5CV%20%3D%20%283.14%29%2818%29%5C%5C%5C%5CV%20%3D%2056.5%20%5C%20in.%5E3%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
17500 i think but u didn’t give enough info so it could be any without the extra info
Answer: 63.3
Step-by-step explanation:
9.5v + 8.7w
v = 3
w = 4
9.5(3) + 8.7(4)
28.5 + 34.8
63.3
It would be 8 + 40 because you multiply the 4 by the 2 and 10
Option A is correct as if we solve the equation We will find that the above equation can be compared to the standard quadratic equation i.e ax^2+bx+c=0
