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4 years ago

It takes Lee Ann 15.2 min to walk 1 mile. How long does it take her to walk 4.34 miles?

Mathematics

2 answers:

SIZIF [17.4K]4 years ago

8 0

66 minutes.hope it helps

Leni [432]4 years ago

5 0

D = r * t
1 mile = r * 15.2 min
1/15.2 = r

4.34 = (1/15.2) *t

4.34* 15.2 = 1 t

t = 65.97 min

t = 66 min

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Read 2 more answers

Noise levels at 3 airports were measured in decibels yielding the following data:

Shalnov [3]

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a) The 90% confidence interval for the mean noise level at such locations

(112.46 , 163.54)

b) The critical value that should be used in constructing the confidence interval

Z₀.₁₀ = 1.645

Step-by-step explanation:

Step(i) :-

Noise levels at 3 airports were measured in decibels yielding the following data

108 146 160

Mean of given data

$x^{-} = \frac{108+146+160}{3} = 138$

x : 108 146 160

x-x⁻ : -30 8 22

(x-x⁻ )² : 900 64 484

Variance σ ² = ∑(x-x⁻ )²/ n-1

= $\frac{900+64+484}{3-1}= 724$

Standard deviation

σ = √724 = 26.90

Step(ii):-

The 90% confidence interval for the mean noise level at such locations

$(x^{-} - Z_{0.90} \frac{S.D}{\sqrt{n} } , (x^{-} + Z_{0.90} \frac{S.D}{\sqrt{n} } )$

The critical value that should be used in constructing the confidence interval

Z₀.₁₀ = 1.645

$(138 - 1.645 \frac{26.90}{\sqrt{3} } , (138 + 1.645 \frac{26.90}{\sqrt{3} } )$

( 138 - 25.54 , 138 + 25.54 )

(112.46 , 163.54)

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