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kykrilka [37]
2 years ago
15

Can someone pls help me solve this .

Mathematics
1 answer:
ASHA 777 [7]2 years ago
6 0
Divide and multiply the numbers :)
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Which answer describes the transformation of f(x)=log2(x−5)−2 from the parent function g(x)=log2x ? A) It is the graph of g(x) s
damaskus [11]

Answer:

It is the graph of g(x) shifted 5 units right and 2 units down.

Step-by-step explanation:

Given : f(x)=log_2(x−5)−2  

the parent function g(x)=log_2(x)

To get f(x) , 5 is subtracted from x

If we add any number with x  then we shift left

If we subtract any number from x  then we shift right

Here 5 is subtracted from x , so we shift 5 units right

Also -2  at the end

If we add any number at the end , then we shift up

if we subtract any number at the end , then we shift down

Here 2 is subtracted at the end , so we shift 2 units down

It is the graph of g(x) shifted 5 units right and 2 units down.

4 0
2 years ago
Can someone help me
erik [133]

Answer:

   6 < x < 23.206

Step-by-step explanation:

To properly answer this question, we need to make the assumption that angle DAC is non-negative and that angle BCA is acute.

The maximum value of the angle DAC can be shown to occur when points B, C, and D are on a circle centered at A*. When that is the case, the sine of half of angle DAC is equal to 16/22 times the sine of half of angle BAC. That is, ...

  (2x -12)/2 = arcsin(16/22×sin(24°))

  x ≈ 23.206°

Of course, the minimum value of angle DAC is 0°, so the minimum value of x is ...

  2x -12 = 0

  x -6 = 0 . . . . . divide by 2

  x = 6 . . . . . . . add 6

Then the range of values of x will be ...

  6 < x < 23.206

_____

* One way to do this is to make use of the law of cosines:

  22² = AB² + AC² -2·AB·AC·cos(48°)

  16² = AD² + AC² -2·AD·AC·cos(2x-12)

The trick is to maximize x while satisfying the constraints that all of the lengths are positive. This will happen when AB=AC=AD, in which case the equations be come ...

  22² = 2·AB²·(1-cos(48°))

  16² = 2·AB²·(1 -cos(2x-12))

The value of AB drops out of the ratio of these equations, and the result for x is as above.

4 0
2 years ago
Read 2 more answers
What is this answer?
Shtirlitz [24]

Answer:

1/2

Step-by-step explanation:

your mom :|

4 0
2 years ago
Read 2 more answers
What is the value of x when 2x+3=3x-4
slavikrds [6]
2x+3=3x-4
try to isolate the x term
you must do the same thing to both sides or else it won't be equal anymore

2x+3=3x-4
add 4 to both sides
2x+3+4=3x+4-4
2x+7=3x+0
subtract 2x from both sides
2x-2x+7=3x-2x
0+7=x
7=x

the answer is x=7
6 0
3 years ago
Read 2 more answers
Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it. lim x→0+ (2x + 1)
ElenaW [278]

\displaystyle\lim_{x\to0^+}(2x+1)\cot x=\lim_{x\to0^+}\frac{2x+1}{\tan x}

As x\to0, the numerator approaches 1 while \tan x\to0, but since x\to0 from above we have \tan x>0, which suggests the limit is +\infty.

3 0
2 years ago
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