Help I will give brainless

Find the equilibrium point for the pair of demand and supply functions. Here q represents the

olya-2409 [2.1K]

The equilibrium point for the pair of demand and supply function is 100

We have been two linear function, one is linear supply function and other is linear demand function.

In general , linear supply function is given as:

Qs = x + yP

Where , Qs = quantity supplied

x = quantity

P = price

And linear demand function is given is :

Qd = x + yP

Where , Qs = quantity supplied

x = quantity

P = price

According to the question,

Linear supply function is q = 300 + 5x

And linear demand function is q = 4800 – 40x

To find the equilibrium point we will put two quantities equal, that is,

Qs = Qd

300 + 5x = 4800 – 40x

5x + 40x = 4800 – 300

45x = 4500

x = 100

Hence the equilibrium point is 100

Learn more about equilibrium point here : brainly.com/question/1915798

#SPJ9

4 0

2 years ago

What is the volume of a sphere when the diameter is 10

Mashutka [201]

if the diameter is 10, its radius is half that, or 5.

$\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=5 \end{cases}\implies V=\cfrac{4\pi (5)^3}{3}\implies V=\cfrac{500\pi }{3} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill V\approx 523.599~\hfill$

8 0

3 years ago

Read 2 more answers

The web logs of a certain website show that the average number of hits in an hour is 75 with a standard deviation equal to 8.6.

Wittaler [7]

Answer:

a) There is a 10.75% probability of observing less than 60 hits in an hour.

b) The 99th percentile of the distribution of the number of hits is 95.21 hits.

c) There is a 24% probability of observing between 80 and 90 hits an hour

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem, we have that

The web logs of a certain website show that the average number of hits in an hour is 75 with a standard deviation equal to 8.6, so $\mu = 75, \sigma = 8.6$ .

a) What’s the probability of observing less than 60 hits in an hour? Use the normal approximation

This is the pvalue of Z when X = 60. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 75}{8.6}$

$Z = -1.74$

$Z = -1.74$ has a pvalue of 0.1075. This means that there is a 10.75% probability of observing less than 60 hits in an hour.

b) What’s the 99th percentile of the distribution of the number of hits?

What is the value of X when Z has a pvalue of 0.99.

Z = 2.35 has a pvalue of 0.99

So

$Z = \frac{X - \mu}{\sigma}$

$2.35 = \frac{X - 75}{8.6}$

$X - 75 = 20.21$

$X = 95.21$

The 99th percentile of the distribution of the number of hits is 95.21 hits.

c) What’s the probability of observing between 80 and 90 hits an hour?

This is the pvalue of the zscore of X = 90 subtracted by the pvalue of the zscore of X = 80.

For X = 90

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{90 - 75}{8.6}$

$Z = 1.74$

$Z = 1.74$ has a pvalue of 0.95907

For X = 80

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{80 - 75}{8.6}$

$Z = 0.58$

$Z = 0.58$ has a pvalue of 0.71904

So

There is a 0.95907 - 0.71904 = 0.24003 = 24% probability of observing between 80 and 90 hits an hour

6 0

3 years ago

PLEASE HELPPPPPP. I NEED IT DONEEEEE.

agasfer [191]

Answer:

1. Couples tickets: $8

Individual tickets: $4

2. Song download cost: $2

Movie download cost: $15

Step-by-step explanation:

You can solve both of these questions by doing system of equations.

Let's start with question 1.

There are 2 variables in this equation:

- Couples tickets price: let's represent these with the letter C

- Individual tickets price: let's represent these with the letter K

Writing the two equations would look this these:

5c + 2k = 48

3c + 2k = 32

Next, isolate a variable. I am going to isolate K in the first equation.

$2k = -5c + 48 \\k = -\frac{5}{2}c + 24$

Now that we isolated a variable we can plug that back in to the second equation:

$3c + 2(-\frac{5}{2}c + 24) = 32\\3c - \frac{10}{2}c + 48 = 32\\3c -5c + 48 = 32\\-2c + 48 = 32\\-2c = -16\\c = 8$

We found that c is equal to 8 so we can put that back in to an equation to solve for k.

5(8) + 2k = 48

40 + 2k = 48

2k = 8

k = 4

Therefore, the price for couples tickets is $8 and the price for individual tickets is $4.

Check #1:

5(8) + 2(4) = 48

40 + 8 = 48

48 = 48

3(8) + 2(4) = 32

24 + 8 = 32

32 + 32

Now, let's go on to question 2.

There are 2 variables in this equation:

- Price of songs downloaded: let's represent these with S

- Price of movies downloaded: let's represent these with M

Writing the two equations would look like this:

15s + 11m = 195

15s + 8m = 150

There is a simple way to answer this system, however.

If you change the bottom equations signs to negative you can minus the second equation from the first equation like this:

15s + 11m = 195

-(15s +8m = 150)

Minus them to get this equation:

3m = 45

Solve

m = 15

We have found that each movie download costs $15, now let's plug this back into an equation:

15s + 11(15) = 195

15s + 165 = 195

15s = 30

s = 2

Each song costs $2 to download.

Check #2:

15(2) + 11(15) = 195

30 + 165 = 195

195 = 195

15(2) + 8(15) = 150

30 + 120 = 150

150 = 150

I hope this helps!!

- Kay :)

6 0

3 years ago

How many different rectangles can you make using 12 toothpicks, use all 12 each time

Savatey [412]

You can essentially make 3 rectangles out of the 12 toothpicks. Remember, squares are technically rectangles.

1. 1 by 5
2. 4 by 2
3. 3 by 3

8 0

3 years ago

Read 2 more answers