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erastovalidia [21]
3 years ago
13

Is this true or false bc i’m not sure pleas help

Mathematics
2 answers:
True [87]3 years ago
6 0

Answer: False.

Step-by-step explanation: The table does not follow a pattern or a relation.

kumpel [21]3 years ago
5 0
The answer is false
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У = 3х – 7<br> у = 3х + 1
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What are you doing if your graphing the points for the first one you start at -7 on the y axis and go up 3 and over tho the left by 1

For the second one you start at 1 on the y axis and go up 3 over the right 1
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In Spring, Jack trimmed his tree 3 in. Shorter. In the summer he trimmed it 5 more inches. The tree is now 45 in. Tall. How tall
sergejj [24]

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Step-by-step explanation:3+5=8

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Write the following as an inequality
Ipatiy [6.2K]

Answer:

3 ≤ w ≤ 4

Step-by-step explanation:

the statements are 3 ≤ w  and 4 ≥ w ( or w ≤ 4 )

These can be combined into the single inequality

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3 years ago
DUE VERY SOON URGENT PLEASE HELP!!
Alla [95]

The values of x are

1. x = 32°,

2. x = 15°,

3. x = 49°,

4. x = 65°,

Explanation:

  • The angle made by any right angle is 90° and the angle made by a straight line is 180°. These are the main equations required to solve the values of x. The first 2 are right angles and the last 2 are straight lines. So the sum of the components within that right angle is 90° and for a straight line is 180°.
  • For diagram 1; 2x° + x° - 6° = 90°, 3x° = 90° + 6° = 96°, x =  \frac{96}{3} = 32°.
  • For diagram 2; 4x° + 3° + x° + 12° = 90°, 5x° = 90° - 15° = 75°, x =  \frac{75}{5} = 15°.
  • For diagram 3; x° + 33° + 2x° = 180°, 3x° = 180° - 33 = 147°, x =  \frac{147}{3} = 49°.
  • For diagram 4; 2x° + 1° + x° - 16° = 180°, 3x° = 180° + 15° = 195°, x = \frac{195}{3} = 65°.
7 0
3 years ago
Find the angle between the vectors u=i-9j and v=8i+5j
Katyanochek1 [597]

Answer: \cos^{-1} \left(\frac{-37}{\sqrt{7298}} \right) \approx 115.665^{\circ}

Step-by-step explanation:

u \cdot v=(1)(8)+(-9)(5)=-37\\\\|u|=\sqrt{1^{2}+(-9)^{2}}=\sqrt{82}\\\\|v|=\sqrt{8^{2}+5^{2}}=\sqrt{89}\\\\\cos \theta=\frac{-37}{\sqrt{82}\sqrt{89}}\\\\\theta=\cos^{-1} \left(\frac{-37}{\sqrt{82}\sqrt{89}} \right)\\\\\theta=\boxed{\cos^{-1} \left(\frac{-37}{\sqrt{7298}} \right) \approx 115.665^{\circ}}

7 0
2 years ago
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