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Anna11 [10]
3 years ago
15

If QRST is a kite, find mZQRS. R (11x - 6) 79° S (4x + 13) T mZQRSI really need help!​

Mathematics
1 answer:
maxonik [38]3 years ago
4 0

Step-by-step explanation:

4x +13 +79+79+ 11x-6 = 360

15x +165 = 360

15x = 195

x =13

QRS = 11(13)-6 = 137

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What is the supplement of 37 degrees?<br> a.53<br> b.22<br> c.147<br> d.143
solniwko [45]
Answer: 143

Explanation: supplementary angles add up to 180 meaning 37 + _ would need to equal 180. The blank number would be 143 since 143 + 37 = 180. Hope this helps!!!
7 0
3 years ago
Read 2 more answers
Can someone help me with this problem
nikdorinn [45]

Answer: x = 33°

Step-by-step explanation: A triangle's angles should all equal 180, so we can set up an equation to help us.

106 + 41 + x = 180

Add 106 and 41

147 + x = 180

Subtract 147 on both sides.

x = 33

And there you go :)

5 0
3 years ago
HELP PLEASE and help me understand
const2013 [10]

When subtracting a number from a negative (like question one) the subtraction sign will now be an addition sign.

1.

6-(-7)=13

For question 2, its simple subtraction. If you subtract a negative from positive, it'l be a negative.

2.

-3 - 3= -6

3.

-15 - 23 = -38

Now we combine my previous explanations. Subtracting a negative from a negative will be like adding (like in question 4)

4.

-9 - (-5)= -4

5.

5 - (-15)=20

6.

78-(-17)=95


Extra Info:

When adding a number (doesnt matter if positive or negative) to a negative it will turn into subtraction.

Examples:

6+(-9)=-3

-9+(-9)= -18

4 0
4 years ago
(x+3)*(x+4)*(x+5)*(x+6)+1
Drupady [299]
There is it hope u have a good day

ANSWER:

6 0
3 years ago
What two numbers add up to 6 and multiply to 12?
GuDViN [60]
Erm

x+y=6
xy=12


x+y=6
y=6-x
sub back

xy=12
x(6-x)=12
6x-x^2=12
x^2-6x=-12
x^2-6x+12=0
quadratic formula
for
ax²+bx+c=0
x= \frac{-b+/- \sqrt{b^2-4ac} }{2a}

for
x²-6x+12=0
a=1
b=-6
c=12
and remember that √-1=i

x= \frac{-(-6)+/- \sqrt{(-6)^2-4(1)(12)} }{2(1)}
x= \frac{6+/- \sqrt{36-48} }{2}
x= \frac{6+/- \sqrt{-12} }{2}
x= \frac{6+/- (\sqrt{-1})(\sqrt{12}) }{2}
x= \frac{6+/- (i)(2\sqrt{3}) }{2}
x= \frac{6+/- 2i\sqrt{3} }{2}
x=3+/-i√3

the numbers are 3+i√3 and 3-i√3
no real numbers tho
7 0
3 years ago
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