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3 years ago

Find the length of the missing side.

Mathematics

1 answer:

melomori [17]3 years ago

6 0

Answer: I’m pretty sure it would be 14

Step-by-step explanation:

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How many inches is 100 meters

gavmur [86]

There is 3937.01 inches in 100 meters.
There is 39.3701 inches in 1 meter
multiply that by 100 and you get your answer
Hope This Helps

8 0

3 years ago

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anonymous 2 years ago Point R is at (2, 1.2) and Point T is at (2, 2.5) on a coordinate grid. The distance between the two point

larisa [96]

I'm on this question too but I think it is 1.3

6 0

3 years ago

What is the equation for a line that passes through the points (5,-3) and (-10,12)?

LekaFEV [45]

Answer: y = -x + 2

Step-by-step explanation:

When x=0, y = 2

When y=0, x = 2

Hope this helps!

5 0

4 years ago

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What point on the line y=9x+8 is closest to the origin

Marat540 [252]

to find the point, find the location

realize that the shortest line that crosses through the origin and y=9x+8 is perpendicular to y=9x+8

perpendicular lines have slopes that multiply to get -1

y=9x+8 has a slope of 9

9*m=-1, m=-1/9

the slope of the mystery line is -1/9

since it passes through the origin, the y intercept is 0

y=(-1/9)x is the equation of the line from the point to the origin

find the intersection of this line and the original line

set them equal to each other

(-1/9)x=9x+8

multily both sides by 9

-x=81x+72

minus 81 both sides

-82x=72

divide both sides by -82

x=-36/41

find y

y=(-1/9)x

y=(-1/9)(-36/41)

y=4/41

the point is $(\frac{-36}{41},\frac{4}{41})$

3 0

3 years ago

A cable hangs between two poles of equal height and 35 feet apart. At a point on the ground directly under the cable and x feet

gayaneshka [121]

Answer:

293.38 pounds

Step-by-step explanation:

We are given that

Distance between poles=35 feet

$h(x)=10+0.1(x^{1.5})$

Weight of cable=10.4 per linear foot

We have to find the weight of the cable.

Differentiate w.r.t

$h'(x)=0.1(1.5)x^{0.5}=0.15x^{0.5}$

$s=2\int_{0}^{17.5}\sqrt{1+(h'(x))^2}dx$

$s=2\int_{0}^{17.5}\sqrt{1+(0.15x^{0.5})^2}dx$

$s=2\int_{0}^{17.5}\sqrt{1+0.0225x}dx$

Let $1+0.0225x=t$

$dx=\frac{1}{0.0225}dt$

$s=\frac{2}{0.0225}\int_{0}^{17.5}\sqrt{t}dt$

$s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}$

$s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}$

$s=\frac{4}{3\times 0.0225}((1+0.0225(17.5))^{\frac{3}{2}-1)$

s=28.21

Weight of cable= $28.21\times 10.4=293.38$ pound

8 0

3 years ago