Answer:
With F represent the variable of interest:



Step-by-step explanation:
For this case we have a normal limits for the temperature Range. The minimum is 660 F and the maximum 790 F.
We can find the midpoint of this interval like this:

And the difference between the midpoint and the limits are:


So then we can create the following inequality:
With F represent the variable of interest.:



74.3 is greater than 7.43
Answer:
22/7×9×3=22×9×3=594÷7=84.85
Answer:
$300
Step-by-step explanation:
1500 • 20%
1500 • 20/100
15 • 20
300
Hope this helps, good luck! :)