Answer: If the measures of the corresponding sides of two triangles are proportional then the triangles are similar. Likewise if the measures of two sides in one triangle are proportional to the corresponding sides in another triangle and the including angles are congruent then the triangles are similar.
Step-by-step explanation:
Answer:
tanA = sinA / cosA = 3/5 / 4/5 = 3/4.
Answer:
490.0...
Step-by-step explanation:
4.9 x 10^2
(squared)
4.9 x 10 x 10
the easiest way to do this is to move the decimal 2 places to the right, as
10 x 10 = 100
4.9 x 100 = 490.0...
Answer:
For Lin's answer
Step-by-step explanation:
When you have a triangle, you can flip it along a side and join that side with the original triangle, so in this case the triangle has been flipped along the longest side and that longest side is now common in both triangles. Now since these are the same triangle the area remains the same.
Now the two triangles form a quadrilateral, which we can prove is a parallelogram by finding out that the opposite sides of the parallelogram are equal since the two triangles are the same(congruent), and they are also parallel as the alternate interior angles of quadrilateral are the same. So the quadrilaral is a paralllelogram, therefore the area of a parallelogram is bh which id 7 * 4 = 7*2=28 sq units.
Since we already established that the triangles in the parallelogram are the same, therefore their areas are also the same, and that the area of the parallelogram is 28 sq units, we can say that A(Q)+A(Q)=28 sq units, therefore 2A(Q)=28 sq units, therefore A(Q)=14 sq units, where A(Q), is the area of triangle Q.
Answer:
Step-by-step explanation:
To find the area subtract the area of the semicircle from the area of the rectangle.
Although the line isn’t there, if you imagine there is one, then you will see that you form a rectangle which is the same line as the semicircle’s diameter.
The area of rectangle is:
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The area of the semicircle;
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*Note here that the radius is half the diameter, so it is 7cm, not 14cm
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Finally subtract the two areas;
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